Solve for h. sqrt –4h = sqrt ( –5 − 5h) h = _____

Square Both Sides: Square both sides of the equation to eliminate the square roots. (sqrt(–4h))^2 = (sqrt(–5 − 5h))^2 –4h = –5 − 5hAdd Terms: Add 5h to both sides of the equation to get all h terms on one side. –4h + 5h = –5 − 5h + 5h h = –5Check Solution: Check for any math errors and verify if the solution makes sense in the original equation. Substitute h = –5 back into the original equation: sqrt(–4(–5)) = sqrt(–5 − 5(–5)) sqrt(20) = sqrt(20) Since both sides are equal, there are no math errors, and the solution is correct.

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Solve for $h$ . $\newline$ $\sqrt{\,-4h} = \sqrt{\,-5 - 5h}$ $\newline$ $h = \,\_\_\_\_$

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Q. Solve for

h

\newline

\sqrt{\,-4h} = \sqrt{\,-5 - 5h}

\newline

h = \,\_\_\_\_

Square Both Sides: Square both sides of the equation to eliminate the square roots. $\newline$ $(\sqrt{-4h})^2 = (\sqrt{-5 - 5h})^2$ $\newline$ $-4h = -5 - 5h$
Add Terms: Add $5h$ to both sides of the equation to get all $h$ terms on one side. $\newline$ $-4h + 5h = -5 - 5h + 5h$ $\newline$ $h = -5$
Check Solution: Check for any math errors and verify if the solution makes sense in the original equation. $\newline$ Substitute $h = -5$ back into the original equation: $\newline$ $\sqrt{-4(-5)} = \sqrt{-5 - 5(-5)}$ $\newline$ $\sqrt{20} = \sqrt{20}$ $\newline$ Since both sides are equal, there are no math errors, and the solution is correct.