Solve for h. sqrt 4h = sqrt ( –2 + 6h) h = _____

Square both sides: Square both sides of the equation to eliminate the square roots. (sqrt(4h))^2 = (sqrt(–2 + 6h))^2 4h = –2 + 6hSubtract 6h: Subtract 6h from both sides to get all the h terms on one side. 4h - 6h = –2 + 6h - 6h -2h = –2Divide by -2: Divide both sides by -2 to solve for h. -2h / -2 = –2 / -2 h = 1

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Solve for $h$ . $\newline$ $\sqrt{4h} = \sqrt{(-2 + 6h)}$ $\newline$ $h =$ _____

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Q. Solve for

h

\newline

\sqrt{4h} = \sqrt{(-2 + 6h)}

\newline

h =

_____

Square both sides: Square both sides of the equation to eliminate the square roots. $\newline$ $(\sqrt{4h})^2 = (\sqrt{\text{–}2 + 6h})^2$ $\newline$ $4h = \text{–}2 + 6h$
Subtract $6$ h: Subtract $6h$ from both sides to get all the $h$ terms on one side. $\newline$ $4h - 6h = -2 + 6h - 6h$ $\newline$ $-2h = -2$
Divide by $-2$ : Divide both sides by $-2$ to solve for $h$ . $\newline$ $\frac{-2h}{-2} = \frac{–2}{-2}$ $\newline$ $h = 1$