Solve for f. sqrt ( 5 − 3f) = sqrt –4f f = _____

Square Both Sides: sqrt(5 − 3f) = sqrt(−4f) Square both sides of the equation to eliminate the square roots. (sqrt(5 − 3f))^2 = (sqrt(−4f))^2 5 − 3f = −4fIsolate Variable: We found 5 − 3f = −4f Isolate the variable on one side of the equation to solve for f. Add 4f to both sides of the equation. 5 − 3f + 4f = −4f + 4f 5 + f = 0Subtract and Solve: We found 5 + f = 0 Subtract 5 from both sides of the equation to solve for f. 5 + f - 5 = 0 - 5 f = −5

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Solve for $f$ . $\newline$ $\sqrt{5 - 3f} = \sqrt{-4f}$ $\newline$ $f =$ _____

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Q. Solve for

f

\newline

\sqrt{5 - 3f} = \sqrt{-4f}

\newline

f =

_____

Square Both Sides: $\sqrt{5 − 3f} = \sqrt{−4f}$ $\newline$ Square both sides of the equation to eliminate the square roots. $\newline$ $(\sqrt{5 − 3f})^2 = (\sqrt{−4f})^2$ $\newline$ $5 − 3f = −4f$
Isolate Variable: We found $5 − 3f = −4f$
Isolate the variable on one side of the equation to solve for $f$ .
Add $4f$ to both sides of the equation.
$5 − 3f + 4f = −4f + 4f$
$5 + f = 0$
Subtract and Solve: We found $5 + f = 0$ Subtract $5$ from both sides of the equation to solve for $f$ . $5 + f - 5 = 0 - 5$ $f = -5$