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Welcome to Bytelearn!
Let’s check out your problem:
Solve for
d
d
d
.
\newline
9
d
−
4
=
5
d
\sqrt{9d - 4} = \sqrt{5d}
9
d
−
4
=
5
d
\newline
d
=
d =
d
=
_____
View step-by-step help
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Math Problems
Precalculus
Solve radical equations
Full solution
Q.
Solve for
d
d
d
.
\newline
9
d
−
4
=
5
d
\sqrt{9d - 4} = \sqrt{5d}
9
d
−
4
=
5
d
\newline
d
=
d =
d
=
_____
Square both sides:
Square both sides of the equation to eliminate the square roots.
\newline
(
9
d
−
4
)
2
=
(
5
d
)
2
(\sqrt{9d − 4})^2 = (\sqrt{5d})^2
(
9
d
−4
)
2
=
(
5
d
)
2
\newline
9
d
−
4
=
5
d
9d − 4 = 5d
9
d
−4
=
5
d
Subtract to combine terms:
Subtract
5
d
5d
5
d
from both sides to get all the
d
d
d
terms on one side.
\newline
9
d
−
5
d
−
4
=
5
d
−
5
d
9d - 5d - 4 = 5d - 5d
9
d
−
5
d
−
4
=
5
d
−
5
d
\newline
4
d
−
4
=
0
4d - 4 = 0
4
d
−
4
=
0
Add to isolate term:
Add
4
4
4
to both sides to isolate the term with
d
d
d
.
\newline
4
d
−
4
+
4
=
0
+
4
4d - 4 + 4 = 0 + 4
4
d
−
4
+
4
=
0
+
4
\newline
4
d
=
4
4d = 4
4
d
=
4
Divide to solve for d:
Divide both sides by
4
4
4
to solve for d.
\newline
4
d
4
=
4
4
\frac{4d}{4} = \frac{4}{4}
4
4
d
=
4
4
\newline
d
=
1
d = 1
d
=
1
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Question
What is the domain of this function?
\newline
y
=
x
y = \sqrt{x}
y
=
x
\newline
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Find the real-number root.
\newline
16
\sqrt{16}
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\newline
\newline
Write your answer in simplified form.
\newline
_
_
_
_
\_\_\_\_
____
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Question
Find the real-number root.
\newline
9
16
\sqrt{\frac{9}{16}}
16
9
\newline
Simplify your answer and write it as a decimal or as a proper or improper fraction.
\newline
_
_
_
_
_
\_\_\_\_\_
_____
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Find the real-number root using a calculator. Round your answer to the nearest thousandth.
\newline
`\sqrt{957} `
\newline
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Question
Multiply. Write your answer in simplest form.
\newline
273
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42
\sqrt{273} \times \sqrt{42}
273
×
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\newline
______
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Posted 1 year ago
Question
Simplify.
\newline
63
4
\sqrt{\frac{63}{4}}
4
63
\newline
______
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Question
Simplify. Rationalize the denominator.
\newline
−
4
9
−
2
\frac{-4}{9 - \sqrt{2}}
9
−
2
−
4
\newline
______
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Posted 1 year ago
Question
Solve for
z
z
z
.
\newline
16
=
z
16 = \sqrt{z}
16
=
z
\newline
z
=
z =
z
=
_____
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Question
Solve for
p
p
p
.
\newline
8
=
p
8 = \sqrt{p}
8
=
p
\newline
p
=
p =
p
=
_____
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Posted 1 year ago
Question
Solve for
p
p
p
.
\newline
4
p
=
10
+
3
p
\sqrt{4p} = \sqrt{10 + 3p}
4
p
=
10
+
3
p
\newline
p
=
p =
p
=
_____
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Posted 9 months ago
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