Solve for d. sqrt ( –9d + 3) = sqrt –10d d = _____

Square both sides: Square both sides of the equation to eliminate the square roots. (sqrt(–9d + 3))^2 = (sqrt(–10d))^2 –9d + 3 = –10dAdd 10d: Add 10d to both sides of the equation to isolate the variable term on one side. –9d + 10d + 3 = –10d + 10d d + 3 = 0Subtract 3: Subtract 3 from both sides of the equation to solve for d. d + 3 - 3 = 0 - 3 d = -3

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Solve for $d$ . $\newline$ $\sqrt{(-9d + 3)} = \sqrt{-10d}$ $\newline$ $d =$ _____

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Precalculus

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Q. Solve for

d

\newline

\sqrt{(-9d + 3)} = \sqrt{-10d}

\newline

d =

_____

Square both sides: Square both sides of the equation to eliminate the square roots. $\newline$ $(\sqrt{-9d + 3})^2 = (\sqrt{-10d})^2$ $\newline$ $-9d + 3 = -10d$
Add $10$ d: Add $10d$ to both sides of the equation to isolate the variable term on one side. $\newline$ $-9d + 10d + 3 = -10d + 10d$ $\newline$ $d + 3 = 0$
Subtract $3$ : Subtract $3$ from both sides of the equation to solve for $d$ . $\newline$ $d + 3 - 3 = 0 - 3$ $\newline$ $d = -3$