Solve for d. sqrt 6d = sqrt ( –3 + 9d) d = _____

Square both sides: Square both sides of the equation to eliminate the square roots. (sqrt(6d))^2 = (sqrt(–3 + 9d))^2 6d = –3 + 9dSubtract d terms: Subtract 9d from both sides to get all the d terms on one side. 6d - 9d = –3 + 9d - 9d -3d = –3Divide by -3: Divide both sides by -3 to solve for d. -3d / -3 = –3 / -3 d = 1

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Solve for $d$ . $\newline$ $\sqrt{6d} = \sqrt{-3 + 9d}$ $\newline$ $d =$ _____

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Q. Solve for

d

\newline

\sqrt{6d} = \sqrt{-3 + 9d}

\newline

d =

_____

Square both sides: Square both sides of the equation to eliminate the square roots. $\newline$ $(\sqrt{6d})^2 = (\sqrt{\text{–}3 + 9d})^2$ $\newline$ $6d = \text{–}3 + 9d$
Subtract $d$ terms: Subtract $9d$ from both sides to get all the $d$ terms on one side. $\newline$ $6d - 9d = -3 + 9d - 9d$ $\newline$ $-3d = -3$
Divide by $-3$ : Divide both sides by $-3$ to solve for $d$ . $\frac{-3d}{-3} = \frac{–3}{-3}$ $d = 1$