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Solve for dd.\newline3d=2+2d\sqrt{3d} = \sqrt{2 + 2d}\newlined=d = _____

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Q. Solve for dd.\newline3d=2+2d\sqrt{3d} = \sqrt{2 + 2d}\newlined=d = _____
  1. Square both sides: Square both sides of the equation to eliminate the square roots.\newline(3d)2=(2+2d)2(\sqrt{3d})^2 = (\sqrt{2 + 2d})^2\newline3d=2+2d3d = 2 + 2d
  2. Subtract to isolate: Subtract 2d2d from both sides to isolate the variable dd on one side of the equation.\newline3d−2d=2+2d−2d3d - 2d = 2 + 2d - 2d\newlined=2d = 2

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