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Welcome to Bytelearn!
Let’s check out your problem:
Solve for
c
c
c
.
\newline
7
c
−
8
=
5
c
\sqrt{7c - 8} = \sqrt{5c}
7
c
−
8
=
5
c
\newline
c
=
c =
c
=
_____
View step-by-step help
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Math Problems
Precalculus
Solve radical equations
Full solution
Q.
Solve for
c
c
c
.
\newline
7
c
−
8
=
5
c
\sqrt{7c - 8} = \sqrt{5c}
7
c
−
8
=
5
c
\newline
c
=
c =
c
=
_____
Square both sides:
Square both sides of the equation to eliminate the square roots.
\newline
(
7
c
−
8
)
2
=
(
5
c
)
2
(\sqrt{7c − 8})^2 = (\sqrt{5c})^2
(
7
c
−8
)
2
=
(
5
c
)
2
\newline
7
c
−
8
=
5
c
7c − 8 = 5c
7
c
−8
=
5
c
Subtract to combine terms:
Subtract
5
c
5c
5
c
from both sides to get the
c
c
c
terms on one side.
\newline
7
c
−
5
c
−
8
=
5
c
−
5
c
7c - 5c - 8 = 5c - 5c
7
c
−
5
c
−
8
=
5
c
−
5
c
\newline
2
c
−
8
=
0
2c - 8 = 0
2
c
−
8
=
0
Add to isolate term:
Add
8
8
8
to both sides to isolate the term with
c
c
c
.
\newline
2
c
−
8
+
8
=
0
+
8
2c - 8 + 8 = 0 + 8
2
c
−
8
+
8
=
0
+
8
\newline
2
c
=
8
2c = 8
2
c
=
8
Divide to solve for c:
Divide both sides by
2
2
2
to solve for
c
c
c
.
2
c
2
=
8
2
\frac{2c}{2} = \frac{8}{2}
2
2
c
=
2
8
c
=
4
c = 4
c
=
4
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What is the domain of this function?
\newline
y
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x
y = \sqrt{x}
y
=
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\newline
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Find the real-number root.
\newline
16
\sqrt{16}
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\newline
\newline
Write your answer in simplified form.
\newline
_
_
_
_
\_\_\_\_
____
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Question
Find the real-number root.
\newline
9
16
\sqrt{\frac{9}{16}}
16
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\newline
Simplify your answer and write it as a decimal or as a proper or improper fraction.
\newline
_
_
_
_
_
\_\_\_\_\_
_____
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Find the real-number root using a calculator. Round your answer to the nearest thousandth.
\newline
`\sqrt{957} `
\newline
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Question
Multiply. Write your answer in simplest form.
\newline
273
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42
\sqrt{273} \times \sqrt{42}
273
×
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\newline
______
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Posted 1 year ago
Question
Simplify.
\newline
63
4
\sqrt{\frac{63}{4}}
4
63
\newline
______
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Question
Simplify. Rationalize the denominator.
\newline
−
4
9
−
2
\frac{-4}{9 - \sqrt{2}}
9
−
2
−
4
\newline
______
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Posted 1 year ago
Question
Solve for
z
z
z
.
\newline
16
=
z
16 = \sqrt{z}
16
=
z
\newline
z
=
z =
z
=
_____
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Question
Solve for
p
p
p
.
\newline
8
=
p
8 = \sqrt{p}
8
=
p
\newline
p
=
p =
p
=
_____
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Posted 1 year ago
Question
Solve for
p
p
p
.
\newline
4
p
=
10
+
3
p
\sqrt{4p} = \sqrt{10 + 3p}
4
p
=
10
+
3
p
\newline
p
=
p =
p
=
_____
Get tutor help
Posted 9 months ago
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