Solve for c. sqrt ( 4 − 3c) = sqrt –4c c = _____

Square Both Sides: sqrt(4 − 3c) = sqrt(−4c) Square both sides of the equation to eliminate the square roots. (sqrt(4 − 3c))^2 = (sqrt(−4c))^2 4 − 3c = −4cIsolate Variable: We found 4 − 3c = −4c Isolate the variable c on one side of the equation to solve for c. Add 4c to both sides of the equation. 4 − 3c + 4c = −4c + 4c 4 + c = 0Subtract and Solve: We found 4 + c = 0 Subtract 4 from both sides to solve for c. 4 + c - 4 = 0 - 4 c = −4

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Solve for $c$ . $\newline$ $\sqrt{4 - 3c} = \sqrt{-4c}$ $\newline$ $c =$ _____

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Q. Solve for

c

\newline

\sqrt{4 - 3c} = \sqrt{-4c}

\newline

c =

_____

Square Both Sides: $\sqrt{4 − 3c} = \sqrt{−4c}$ $\newline$ Square both sides of the equation to eliminate the square roots. $\newline$ $(\sqrt{4 − 3c})^2 = (\sqrt{−4c})^2$ $\newline$ $4 − 3c = −4c$
Isolate Variable: We found $4 - 3c = -4c$
Isolate the variable $c$ on one side of the equation to solve for $c$ .
Add $4c$ to both sides of the equation.
$4 - 3c + 4c = -4c + 4c$
$4 + c = 0$
Subtract and Solve: We found $4 + c = 0$ Subtract $4$ from both sides to solve for $c$ . $4 + c - 4 = 0 - 4$ $c = -4$