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Solve for bb.\newline5b=3b+10\sqrt{\,-5b} = \sqrt{\,-3b + 10}\newlineb=_____b = \,\_\_\_\_\_

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Q. Solve for bb.\newline5b=3b+10\sqrt{\,-5b} = \sqrt{\,-3b + 10}\newlineb=_____b = \,\_\_\_\_\_
  1. Square both sides: Square both sides of the equation to eliminate the square roots.\newline(5b)2=(3b+10)2(\sqrt{-5b})^2 = (\sqrt{-3b + 10})^2\newline5b=3b+10-5b = -3b + 10
  2. Move terms involving bb: Move all terms involving bb to one side of the equation.5b+3b=3b+3b+10\,-5b + 3b = -3b + 3b + 102b=10\,-2b = 10
  3. Divide by 2-2: Divide both sides by extendash22 to solve for bb. \newline2b2=102\frac{-2b}{-2} = \frac{10}{-2}\newlineb=5b = -5

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