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Let’s check out your problem:
Solve for
b
b
b
.
\newline
(
−
4
−
5
b
)
=
−
3
b
\sqrt{(-4 - 5b)} = \sqrt{-3b}
(
−
4
−
5
b
)
=
−
3
b
\newline
b
=
b =
b
=
_____
View step-by-step help
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Math Problems
Precalculus
Solve radical equations
Full solution
Q.
Solve for
b
b
b
.
\newline
(
−
4
−
5
b
)
=
−
3
b
\sqrt{(-4 - 5b)} = \sqrt{-3b}
(
−
4
−
5
b
)
=
−
3
b
\newline
b
=
b =
b
=
_____
Square both sides:
Square both sides of the equation to eliminate the square roots.
\newline
(
−
4
−
5
b
)
2
=
(
−
3
b
)
2
(\sqrt{-4 - 5b})^2 = (\sqrt{-3b})^2
(
−
4
−
5
b
)
2
=
(
−
3
b
)
2
\newline
−
4
−
5
b
=
−
3
b
-4 - 5b = -3b
−
4
−
5
b
=
−
3
b
Move terms with
b
b
b
:
Move all terms containing
b
b
b
to one side of the equation.\(\newline\)
−
4
=
−
3
b
+
5
b
-4 = -3b + 5b
−
4
=
−
3
b
+
5
b
\(\newline\)
−
4
=
2
b
-4 = 2b
−
4
=
2
b
Divide by
2
2
2
:
Divide both sides by
2
2
2
to solve for
b
b
b
.
−
4
2
=
2
b
2
\frac{-4}{2} = \frac{2b}{2}
2
−
4
=
2
2
b
b
=
−
2
b = -2
b
=
−
2
More problems from Solve radical equations
Question
What is the domain of this function?
\newline
y
=
x
y = \sqrt{x}
y
=
x
\newline
Choices:
\newline
{
x
∣
x
≥
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}
\{x|x \geq 0\}
{
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∣
x
≥
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}
\newline
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{
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\{x | x < 0\}
{
x
∣
x
<
0
}
\newline
{
x
∣
x
>
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\{x|x>0\}
{
x
∣
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Posted 1 year ago
Question
Find the real-number root.
\newline
16
\sqrt{16}
16
\newline
\newline
Write your answer in simplified form.
\newline
_
_
_
_
\_\_\_\_
____
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Posted 1 year ago
Question
Find the real-number root.
\newline
9
16
\sqrt{\frac{9}{16}}
16
9
\newline
Simplify your answer and write it as a decimal or as a proper or improper fraction.
\newline
_
_
_
_
_
\_\_\_\_\_
_____
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Posted 1 year ago
Question
Find the real-number root using a calculator. Round your answer to the nearest thousandth.
\newline
`\sqrt{957} `
\newline
_______
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Posted 1 year ago
Question
Multiply. Write your answer in simplest form.
\newline
273
×
42
\sqrt{273} \times \sqrt{42}
273
×
42
\newline
______
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Posted 1 year ago
Question
Simplify.
\newline
63
4
\sqrt{\frac{63}{4}}
4
63
\newline
______
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Posted 1 year ago
Question
Simplify. Rationalize the denominator.
\newline
−
4
9
−
2
\frac{-4}{9 - \sqrt{2}}
9
−
2
−
4
\newline
______
Get tutor help
Posted 1 year ago
Question
Solve for
z
z
z
.
\newline
16
=
z
16 = \sqrt{z}
16
=
z
\newline
z
=
z =
z
=
_____
Get tutor help
Posted 1 year ago
Question
Solve for
p
p
p
.
\newline
8
=
p
8 = \sqrt{p}
8
=
p
\newline
p
=
p =
p
=
_____
Get tutor help
Posted 1 year ago
Question
Solve for
p
p
p
.
\newline
4
p
=
10
+
3
p
\sqrt{4p} = \sqrt{10 + 3p}
4
p
=
10
+
3
p
\newline
p
=
p =
p
=
_____
Get tutor help
Posted 9 months ago
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