Solve for b. Express your answer in simplest radical form if necessary. b=sqrt96*sqrt96 Answer: b=

Write Problem: First, let's write down the problem: b = sqrt(96) * sqrt(96).Apply Rule: Now, we know that sqrt(a) * sqrt(a) = a. So, b = 96.Check Simplification: But wait, we need to check if 96 can be simplified further. The prime factorization of 96 is 2^5 * 3. So, b = sqrt(2^5 * 3) * sqrt(2^5 * 3).Take Out Factors: Since we have a pair of each prime factor under the square root, we can take out one of each pair. So, b = 2^2 * 3 * sqrt(2).Simplify Expression: That simplifies to b = 4 * 3 * sqrt(2).Multiply Numbers: Finally, we multiply the numbers outside the square root. So, b = 12 * sqrt(2).

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Solve for
b. Express your answer in simplest radical form if necessary.

b=sqrt96*sqrt96
Answer:
b=

Solve for $b$ . Express your answer in simplest radical form if necessary. $\newline$ $b=\sqrt{96} \cdot \sqrt{96}$ $\newline$ Answer: $b=$

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Math Problems

Algebra 2

Multiply radical expressions

Full solution

Q. Solve for

b

. Express your answer in simplest radical form if necessary.

\newline

b=\sqrt{96} \cdot \sqrt{96}

\newline

Answer:

b=

Write Problem: First, let's write down the problem: $b = \sqrt{96} \times \sqrt{96}$ .
Apply Rule: Now, we know that $\sqrt{a} \times \sqrt{a} = a$ . So, $b = 96$ .
Check Simplification: But wait, we need to check if $96$ can be simplified further. The prime factorization of $96$ is $2^5 \times 3$ . So, $b = \sqrt{2^5 \times 3} \times \sqrt{2^5 \times 3}$ .
Take Out Factors: Since we have a pair of each prime factor under the square root, we can take out one of each pair. So, $b = 2^2 \times 3 \times \sqrt{2}$ .
Simplify Expression: That simplifies to $b = 4 \times 3 \times \sqrt{2}$ .
Multiply Numbers: Finally, we multiply the numbers outside the square root. So, $b = 12 \times \sqrt{2}$ .