Solve for all real values of x. x^(2)-9=0 Answer: x=

Set up the equation: Set up the equation. We have the equation x^(2) - 9 = 0. To solve for x, we need to find the values that make this equation true.Factor the left side: Factor the left side of the equation. The left side of the equation is a difference of squares, which can be factored into (x + 3)(x - 3). So, x^(2) - 9 = (x + 3)(x - 3).Set each factor equal: Set each factor equal to zero. Since the product of the factors is zero, we can set each factor equal to zero and solve for x. x + 3 = 0 or x - 3 = 0.Solve each equation for x: Solve each equation for x. For the first equation, x + 3 = 0, we subtract 3 from both sides to get x = -3. For the second equation, x - 3 = 0, we add 3 to both sides to get x = 3.

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Solve for all real values of
x.

x^(2)-9=0
Answer:
x=

Solve for all real values of $x$ . $\newline$ $x^{2}-9=0$ $\newline$ Answer: $x=$ $\newline$

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Algebra 2

Solve a quadratic equation using square roots

Full solution

Q. Solve for all real values of

x

\newline

x^{2}-9=0

\newline

Answer:

x=

\newline

Set up the equation: Set up the equation. $\newline$ We have the equation $x^{2} - 9 = 0$ . $\newline$ To solve for $x$ , we need to find the values that make this equation true.
Factor the left side: Factor the left side of the equation. $\newline$ The left side of the equation is a difference of squares, which can be factored into $(x + 3)(x - 3)$ . $\newline$ So, $x^{2} - 9 = (x + 3)(x - 3)$ .
Set each factor equal: Set each factor equal to zero. $\newline$ Since the product of the factors is zero, we can set each factor equal to zero and solve for $x$ . $\newline$ $x + 3 = 0$ or $x - 3 = 0$ .
Solve each equation for $x$ : Solve each equation for $x$ . For the first equation, $x + 3 = 0$ , we subtract $3$ from both sides to get $x = -3$ . For the second equation, $x - 3 = 0$ , we add $3$ to both sides to get $x = 3$ .