Solve for all real values of x. x^(2)-8=0 Answer: x=

Set up equation: Set up the equation to solve for x. We have the equation x^2 - 8 = 0. To find the values of x, we need to isolate x on one side of the equation.Add 8: Add 8 to both sides of the equation to isolate the x^2 term. x^2 - 8 + 8 = 0 + 8 This simplifies to: x^2 = 8Take square root: Take the square root of both sides of the equation to solve for x. x = ±sqrt(8)Simplify square root: Simplify the square root of 8. Since 8 is 4 times 2 and the square root of 4 is 2, we can simplify sqrt(8) to 2*sqrt(2). x = ±2*sqrt(2)

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Solve for all real values of
x.

x^(2)-8=0
Answer:
x=

Solve for all real values of $x$ . $\newline$ $x^{2}-8=0$ $\newline$ Answer: $x=$ $\newline$

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Algebra 2

Solve a quadratic equation using square roots

Full solution

Q. Solve for all real values of

x

\newline

x^{2}-8=0

\newline

Answer:

x=

\newline

Set up equation: Set up the equation to solve for $x$ . We have the equation $x^2 - 8 = 0$ . To find the values of $x$ , we need to isolate $x$ on one side of the equation.
Add $8$ : Add $8$ to both sides of the equation to isolate the $x^2$ term. $\newline$ $x^2 - 8 + 8 = 0 + 8$ $\newline$ This simplifies to: $\newline$ $x^2 = 8$
Take square root: Take the square root of both sides of the equation to solve for $x$ . $x = \pm\sqrt{8}$
Simplify square root: Simplify the square root of $8$ . $\newline$ Since $8$ is $4$ times $2$ and the square root of $4$ is $2$ , we can simplify $\sqrt{8}$ to $2\sqrt{2}$ . $\newline$ $x = \pm 2\sqrt{2}$