Solve for all real values of x. x^(2)-16=0 Answer: x=

Set up the equation: Set up the equation. We are given the equation x^(2) - 16 = 0. To solve for x, we need to find the values that make this equation true.Factor the left side: Factor the left side of the equation. The left side of the equation is a difference of squares, which can be factored as (x + 4)(x - 4). So, x^(2) - 16 = (x + 4)(x - 4) = 0.Use zero product property: Use the zero product property. If the product of two factors is zero, then at least one of the factors must be zero. Therefore, we set each factor equal to zero and solve for x: x + 4 = 0 or x - 4 = 0.Solve for x: Solve each equation for x. For the first equation, x + 4 = 0, we subtract 4 from both sides to get x = -4. For the second equation, x - 4 = 0, we add 4 to both sides to get x = 4.

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Solve for all real values of
x.

x^(2)-16=0
Answer:
x=

Solve for all real values of $x$ . $\newline$ $x^{2}-16=0$ $\newline$ Answer: $x=$

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Algebra 2

Solve a quadratic equation using square roots

Full solution

Q. Solve for all real values of

x

\newline

x^{2}-16=0

\newline

Answer:

x=

Set up the equation: Set up the equation. $\newline$ We are given the equation $x^{2} - 16 = 0$ . $\newline$ To solve for $x$ , we need to find the values that make this equation true.
Factor the left side: Factor the left side of the equation. $\newline$ The left side of the equation is a difference of squares, which can be factored as $(x + 4)(x - 4)$ . $\newline$ So, $x^{2} - 16 = (x + 4)(x - 4) = 0$ .
Use zero product property: Use the zero product property. $\newline$ If the product of two factors is zero, then at least one of the factors must be zero. $\newline$ Therefore, we set each factor equal to zero and solve for $x$ : $\newline$ $x + 4 = 0$ or $x - 4 = 0$ .
Solve for x: Solve each equation for x. $\newline$ For the first equation, $x + 4 = 0$ , we subtract $4$ from both sides to get $x = -4$ . $\newline$ For the second equation, $x - 4 = 0$ , we add $4$ to both sides to get $x = 4$ .