Solve for a. sqrt ( –a + 6) = sqrt –3a a = _____

Square both sides: Square both sides of the equation to eliminate the square roots. (sqrt(–a + 6))^2 = (sqrt(–3a))^2 –a + 6 = –3aAdd 'a': Add 'a' to both sides of the equation to start isolating the variable 'a'. –a + a + 6 = –3a + a 6 = –2aDivide by -2: Divide both sides of the equation by -2 to solve for 'a'. 6 / -2 = –2a / -2 –3 = a

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Solve for $a$ . $\newline$ $\sqrt{(-a + 6)} = \sqrt{-3a}$ $\newline$ $a =$ _____

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Precalculus

Solve radical equations

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Q. Solve for

a

\newline

\sqrt{(-a + 6)} = \sqrt{-3a}

\newline

a =

_____

Square both sides: Square both sides of the equation to eliminate the square roots. $\newline$ $(\sqrt{-a + 6})^2 = (\sqrt{-3a})^2$ $\newline$ $-a + 6 = -3a$
Add ' extit{a}': Add ' extit{a}' to both sides of the equation to start isolating the variable ' extit{a}'. $\newline$ $-a + a + 6 = -3a + a$ $\newline$ $6 = -2a$
Divide by $-2$ : Divide both sides of the equation by $-2$ to solve for 'a'. $\newline$ $\frac{6}{-2} = \frac{–2a}{-2}$ $\newline$ $–3 = a$