Solve for a. sqrt ( –4a + 4) = sqrt –6a a = _____

Square Both Sides: Square both sides of the equation to eliminate the square roots. (sqrt(–4a + 4))^2 = (sqrt(–6a))^2 –4a + 4 = –6aAdd 4a: Add 4a to both sides to get all the terms with 'a' on one side. –4a + 4 + 4a = –6a + 4a 4 = –2aDivide by -2: Divide both sides by -2 to solve for 'a'. 4 / -2 = –2a / -2 a = -2

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Solve for $a$ . $\newline$ $\sqrt{(-4a + 4)} = \sqrt{-6a}$ $\newline$ $a =$ _____

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Precalculus

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Q. Solve for

a

\newline

\sqrt{(-4a + 4)} = \sqrt{-6a}

\newline

a =

_____

Square Both Sides: Square both sides of the equation to eliminate the square roots. $\newline$ $(\sqrt{\text{–}4a + 4})^2 = (\sqrt{\text{–}6a})^2$ $\newline$ $\text{–}4a + 4 = \text{–}6a$
Add $4$ a: Add $4a$ to both sides to get all the terms with ' $a$ ' on one side. $\newline$ $-4a + 4 + 4a = -6a + 4a$ $\newline$ $4 = -2a$
Divide by $-2$ : Divide both sides by $-2$ to solve for 'a'. $\newline$ $\frac{4}{-2} = \frac{–2a}{-2}$ $\newline$ $a = -2$