Solve for a. Express your answer in simplest radical form if necessary. a=root(3)(-87)*root(3)(-87)*root(3)(-87) Answer: a=

Calculate Cube Root Product: a = root(3)(-87) * root(3)(-87) * root(3)(-87) We know that multiplying three cube roots of the same number is the same as taking the cube root of the product of the numbers.Multiply -87 Three Times: a = root(3)(-87 * -87 * -87) When we multiply -87 three times, we get -87^3.Calculate -87^3: a = root(3)(-87^3) Now we calculate -87^3.Take Cube Root of -658503: a = root(3)(-658503) We take the cube root of -658503.Final Result: a = -87 The cube root of -658503 is -87, because (-87) * (-87) * (-87) = -658503.

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Solve for
a. Express your answer in simplest radical form if necessary.

a=root(3)(-87)*root(3)(-87)*root(3)(-87)
Answer:
a=

Solve for $a$ . Express your answer in simplest radical form if necessary. $\newline$ $a=\sqrt[3]{-87} \cdot \sqrt[3]{-87} \cdot \sqrt[3]{-87}$ $\newline$ Answer: $a=$

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Math Problems

Algebra 1

Multiplication with rational exponents

Full solution

Q. Solve for

a

. Express your answer in simplest radical form if necessary.

\newline

a=\sqrt[3]{-87} \cdot \sqrt[3]{-87} \cdot \sqrt[3]{-87}

\newline

Answer:

a=

Calculate Cube Root Product: $a = \sqrt[3]{-87} \times \sqrt[3]{-87} \times \sqrt[3]{-87}$ $\newline$ We know that multiplying three cube roots of the same number is the same as taking the cube root of the product of the numbers.
Multiply $-87$ Three Times: $a = \sqrt[3]{(-87) \times (-87) \times (-87)}$ $\newline$ When we multiply $-87$ three times, we get $-87^3$ .
Calculate $-87^3$ : $a = \sqrt[3]{-87^3}$ $\newline$ Now we calculate $-87^3$ .
Take Cube Root of $-658503$ : $a = \sqrt[3]{-658503}$ $\newline$ We take the cube root of $-658503$ .
Final Result: $a = -87$ $\newline$ The cube root of $-658503$ is $-87$ , because $(-87) \times (-87) \times (-87) = -658503$ .