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Solve.\newline2x+2y=102x + 2y = 10\newliney=−1y = -1\newline(_____, _____)

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Q. Solve.\newline2x+2y=102x + 2y = 10\newliney=−1y = -1\newline(_____, _____)
  1. Substitute yy in first equation: Substitute the value of yy into the first equation.\newlineGiven y=−1y = -1, substitute −1-1 for yy in 2x+2y=102x + 2y = 10.\newline2x+2(−1)=102x + 2(-1) = 10
  2. Simplify and solve for x: Simplify the equation and solve for x. \newline2x−2=102x - 2 = 10\newlineAdd 22 to both sides to isolate the term with xx.\newline2x−2+2=10+22x - 2 + 2 = 10 + 2\newline2x=122x = 12
  3. Divide to find xx: Divide both sides by 22 to find the value of xx.2x2=122\frac{2x}{2} = \frac{12}{2}x=6x = 6
  4. Write solution as ordered pair: Write the solution as an ordered pair.\newlineWe have found x=6x = 6 and y=−1y = -1.\newlineThe solution in the form of an ordered pair is (6,−1)(6, -1).

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