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sin^(-1)(-1)=

sin1(1) \sin ^{-1}(-1) =

Full solution

Q. sin1(1) \sin ^{-1}(-1) =
  1. Question Prompt: Question prompt: What is the value of sin1(1)\sin^{-1}(-1)?
  2. Understand the Problem: Understand the problem.\newlineWe need to find the angle whose sine is 1-1.
  3. Recall Definition: Recall the definition of the inverse sine function. The inverse sine function, sin1(x)\sin^{-1}(x), gives us the angle whose sine is xx.
  4. Recall Range: Recall the range of the inverse sine function.\newlineThe range of sin1(x)\sin^{-1}(x) is from π2-\frac{\pi}{2} to π2\frac{\pi}{2}.
  5. Identify Angle: Identify the angle within the range of the inverse sine function whose sine is 1-1.\newlineThe sine of π/2-\pi/2 is 1-1.
  6. Write Final Answer: Write the final answer. sin1(1)=π2\sin^{-1}(-1) = -\frac{\pi}{2}

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