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Let’s check out your problem:
Simplify to create an equivalent expression.
\newline
19
−
6
(
−
k
+
4
)
19-6(-k+4)
19
−
6
(
−
k
+
4
)
\newline
Choose
1
1
1
answer:
\newline
(A)
6
k
−
5
6k-5
6
k
−
5
\newline
(B)
−
6
k
−
5
-6k-5
−
6
k
−
5
\newline
(C)
6
k
+
9
6k+9
6
k
+
9
\newline
(D)
6
k
+
5
6k+5
6
k
+
5
View step-by-step help
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Math Problems
Algebra 2
Sum of finite series starts from 1
Full solution
Q.
Simplify to create an equivalent expression.
\newline
19
−
6
(
−
k
+
4
)
19-6(-k+4)
19
−
6
(
−
k
+
4
)
\newline
Choose
1
1
1
answer:
\newline
(A)
6
k
−
5
6k-5
6
k
−
5
\newline
(B)
−
6
k
−
5
-6k-5
−
6
k
−
5
\newline
(C)
6
k
+
9
6k+9
6
k
+
9
\newline
(D)
6
k
+
5
6k+5
6
k
+
5
Distribute
−
6
-6
−
6
:
First, distribute the
−
6
-6
−
6
to both terms inside the parentheses.
\newline
−
6
×
(
−
k
)
+
−
6
×
4
-6 \times (-k) + -6 \times 4
−
6
×
(
−
k
)
+
−
6
×
4
Combine terms:
The distribution gives us
6
k
−
24
6k - 24
6
k
−
24
.
Add like terms:
Now, combine the like terms by adding
19
19
19
and
−
24
-24
−
24
.
19
−
24
=
−
5
19 - 24 = -5
19
−
24
=
−
5
Final expression:
The final expression after combining like terms is
6
k
−
5
6k - 5
6
k
−
5
.
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2, 10, 50, 250, \ldots
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Choices:Choices:
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\text{[A]arithmetic}
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Classify the series.
∑
n
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Choices:
\newline
[A]arithmetic
\text{[A]arithmetic}
[A]arithmetic
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[B]geometric
\text{[B]geometric}
[B]geometric
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[C]both
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Question
Find the first three partial sums of the series.
\newline
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\newline
S
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=
S_1 =
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1
=
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\newline
S
2
=
S_2 =
S
2
=
____
\newline
S
3
=
S_3 =
S
3
=
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Find the third partial sum of the series.
\newline
3
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9
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15
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21
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27
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33
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\newline
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=
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Find the first three partial sums of the series.
\newline
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Write your answers as integers or fractions in simplest form.
\newline
S
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=
S_1 =
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1
=
____
\newline
S
2
=
S_2 =
S
2
=
____
\newline
S
3
=
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=
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Question
Does the infinite geometric series converge or diverge?
\newline
1
+
3
4
+
9
16
+
27
64
+
⋯
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+
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\newline
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\newline
[A]converge
\text{[A]converge}
[A]converge
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[B]diverge
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