Simplify to a single trig function with no denominator. (cot^(2)theta)/(csc^(2)theta) Answer: theta

Express cot(theta): Express cot(theta) and csc(theta) in terms of sin(theta) and cos(theta) as cot(theta) = cos(theta)/sin(theta) and csc(theta) = 1/sin(theta).Substitute cot(theta): Substitute cot(theta) and csc(theta) in the given expression with their respective expressions in terms of sin(theta) and cos(theta) to get (cos(theta)/sin(theta))^2 / (1/sin(theta))^2.Simplify the expression: Simplify the expression by multiplying the numerator and the denominator by sin(theta)^2 to get (cos(theta)^2)/(sin(theta)^2) * (sin(theta)^2)/(1).Cancel out terms: Cancel out the sin(theta)^2 terms in the numerator and the denominator to get cos(theta)^2.

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Simplify to a single trig function with no denominator.

(cot^(2)theta)/(csc^(2)theta)
Answer:

theta

Simplify to a single trig function with no denominator. $\newline$ $\frac{\cot ^{2} \theta}{\csc ^{2} \theta}$ $\newline$ Answer:

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Algebra 2

Simplify expressions using trigonometric identities

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Q. Simplify to a single trig function with no denominator.

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\frac{\cot ^{2} \theta}{\csc ^{2} \theta}

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Answer:

Express $\cot(\theta)$ : Express $\cot(\theta)$ and $\csc(\theta)$ in terms of $\sin(\theta)$ and $\cos(\theta)$ as $\cot(\theta) = \frac{\cos(\theta)}{\sin(\theta)}$ and $\csc(\theta) = \frac{1}{\sin(\theta)}$ .
Substitute $\cot(\theta)$ : Substitute $\cot(\theta)$ and $\csc(\theta)$ in the given expression with their respective expressions in terms of $\sin(\theta)$ and $\cos(\theta)$ to get $\left(\frac{\cos(\theta)}{\sin(\theta)}\right)^2 / \left(\frac{1}{\sin(\theta)}\right)^2$ .
Simplify the expression: Simplify the expression by multiplying the numerator and the denominator by $\sin(\theta)^2$ to get $\frac{\cos(\theta)^2}{\sin(\theta)^2} \cdot \frac{\sin(\theta)^2}{1}$ .
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