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Simplify the following expression to simplest form using only positive exponents.

(64x^(-2)y^(-10))^((3)/(2))
Answer:

Simplify the following expression to simplest form using only positive exponents.\newline(64x2y10)32 \left(64 x^{-2} y^{-10}\right)^{\frac{3}{2}} \newlineAnswer:

Full solution

Q. Simplify the following expression to simplest form using only positive exponents.\newline(64x2y10)32 \left(64 x^{-2} y^{-10}\right)^{\frac{3}{2}} \newlineAnswer:
  1. Understand Expression and Rule: Understand the expression and the exponent rule.\newlineThe expression is (64x2y10)32(64x^{-2}y^{-10})^{\frac{3}{2}}. We need to apply the power of a power rule, which states that (am)n=amn(a^m)^n = a^{m*n}. We will apply this rule to each part of the expression separately.
  2. Apply Power of Power Rule to Coefficient: Apply the power of a power rule to the numerical coefficient.\newlineThe numerical coefficient is 6464, which is a perfect square (82)(8^2). We raise it to the power of (3/2)(3/2), which is the same as taking the square root and then cubing the result.\newline(64)(3/2)=(82)(3/2)=82(3/2)=83=512(64)^{(3/2)} = (8^2)^{(3/2)} = 8^{2*(3/2)} = 8^3 = 512.
  3. Apply Power of Power Rule to x Term: Apply the power of a power rule to the x term.\newlineThe x term is x2x^{-2}. We raise it to the power of (3/2)(3/2).\newline(x2)(3/2)=x(2)(3/2)=x3(x^{-2})^{(3/2)} = x^{(-2)*(3/2)} = x^{-3}.\newlineTo express the exponent as positive, we take the reciprocal of x3x^3.\newlinex3=1x3x^{-3} = \frac{1}{x^3}.
  4. Apply Power of Power Rule to yy Term: Apply the power of a power rule to the yy term.\newlineThe yy term is y10y^{-10}. We raise it to the power of (3/2)(3/2).\newline(y10)(3/2)=y(10)(3/2)=y15(y^{-10})^{(3/2)} = y^{(-10)*(3/2)} = y^{-15}.\newlineTo express the exponent as positive, we take the reciprocal of y15y^{15}.\newliney15=1y15y^{-15} = \frac{1}{y^{15}}.
  5. Combine Results: Combine the results from Steps 22, 33, and 44.\newlineWe have 512512 for the numerical coefficient, 1/x31/x^3 for the x term, and 1/y151/y^{15} for the y term. Combining these, we get:\newline512×(1/x3)×(1/y15)=512/(x3×y15)512 \times (1/x^3) \times (1/y^{15}) = 512 / (x^3 \times y^{15}).

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