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Let’s check out your problem:
Simplify the expression. Write your answers using
integers
or improper
fractions
.
\newline
−
5
2
a
−
5
(
a
+
1
2
)
-\frac{5}{2} a-5\left(a+\frac{1}{2}\right)
−
2
5
a
−
5
(
a
+
2
1
)
\newline
Answer:
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Math Problems
Algebra 1
Multiplication with rational exponents
Full solution
Q.
Simplify the expression. Write your answers using integers or improper fractions.
\newline
−
5
2
a
−
5
(
a
+
1
2
)
-\frac{5}{2} a-5\left(a+\frac{1}{2}\right)
−
2
5
a
−
5
(
a
+
2
1
)
\newline
Answer:
Distribute and Multiply:
Distribute the
−
5
-5
−
5
across the parentheses.
\newline
−
5
×
a
+
−
5
×
(
1
2
)
-5 \times a + -5 \times (\frac{1}{2})
−
5
×
a
+
−
5
×
(
2
1
)
Combine Like Terms:
Perform the multiplication.
\newline
−
5
a
−
(
5
2
)
-5a - \left(\frac{5}{2}\right)
−
5
a
−
(
2
5
)
Convert to Fractions:
Combine the like terms, which are the terms with the variable
a
a
a
.
−
5
2
a
−
5
a
-\frac{5}{2}a - 5a
−
2
5
a
−
5
a
Add and Combine Fractions:
Convert
−
5
a
-5a
−
5
a
to a
fraction
with the same denominator as
−
(
5
/
2
)
a
-(5/2)a
−
(
5/2
)
a
to combine them.
\newline
−
5
a
=
−
5
×
(
2
/
2
)
a
=
−
(
10
/
2
)
a
-5a = -5 \times (2/2)a = -(10/2)a
−
5
a
=
−
5
×
(
2/2
)
a
=
−
(
10/2
)
a
Simplify Expression:
Add the fractions
−
5
2
a
-\frac{5}{2}a
−
2
5
a
and
−
10
2
a
-\frac{10}{2}a
−
2
10
a
.
−
5
2
a
−
10
2
a
=
−
5
+
10
2
⋅
a
=
−
15
2
a
-\frac{5}{2}a - \frac{10}{2}a = -\frac{5 + 10}{2} \cdot a = -\frac{15}{2}a
−
2
5
a
−
2
10
a
=
−
2
5
+
10
⋅
a
=
−
2
15
a
Simplify Expression:
Add the fractions
−
5
2
a
-\frac{5}{2}a
−
2
5
a
and
−
10
2
a
-\frac{10}{2}a
−
2
10
a
.
−
5
2
a
−
10
2
a
=
−
5
+
10
2
⋅
a
=
−
15
2
a
-\frac{5}{2}a - \frac{10}{2}a = -\frac{5 + 10}{2} \cdot a = -\frac{15}{2}a
−
2
5
a
−
2
10
a
=
−
2
5
+
10
⋅
a
=
−
2
15
a
Simplify the expression by combining the constants.
−
15
2
a
-\frac{15}{2}a
−
2
15
a
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Simplify.
\newline
8
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81^{\frac{1}{2}}
8
1
2
1
\newline
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\newline
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\newline
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\newline
w
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w
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w
3
7
w
3
4
\newline
Write your answer in the form
A
A
A
or
A
B
\frac{A}{B}
B
A
, where
A
A
A
and
B
B
B
are constants or variable expressions that have no variables in common. All exponents in your answer should be positive.
\newline
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Simplify. Assume all variables are positive.
\newline
(
2
r
1
3
)
8
(2r^{\frac{1}{3}})^8
(
2
r
3
1
)
8
\newline
\newline
Write your answer in the form
A
A
A
or
A
B
\frac{A}{B}
B
A
, where
A
A
A
and
B
B
B
are constants or variable expressions that have no variables in common. All exponents in your answer should be positive.
\newline
______
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Question
Simplify. Assume all variables are positive.
\newline
v
7
4
⋅
v
9
4
v^{\frac{7}{4}} \cdot v^{\frac{9}{4}}
v
4
7
⋅
v
4
9
\newline
\newline
Write your answer in the form
A
A
A
or
A
B
\frac{A}{B}
B
A
, where
A
A
A
and
B
B
B
are constants or variable expressions that have no variables in common. All exponents in your answer should be positive.
\newline
______
\newline
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Question
Simplify.
\newline
1
1
4
⋅
1
1
4
1^{\frac{1}{4}} \cdot 1^{\frac{1}{4}}
1
4
1
⋅
1
4
1
\newline
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Posted 9 months ago
Question
Simplify.
\newline
3
2
(
−
1
/
5
)
32^{(-1/5)}
3
2
(
−
1/5
)
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Posted 1 year ago
Question
Simplify. Assume all variables are positive.
\newline
w
3
2
w
5
2
\frac{w^{\frac{3}{2}}}{w^{\frac{5}{2}}}
w
2
5
w
2
3
\newline
\newline
Write your answer in the form
A
A
A
or
A
B
\frac{A}{B}
B
A
, where
A
A
A
and
B
B
B
are constants or variable expressions that have no variables in common. All exponents in your answer should be positive.
\newline
______
\newline
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Question
Simplify. Assume all variables are positive.
\newline
(
27
x
)
2
3
(27x)^{\frac{2}{3}}
(
27
x
)
3
2
\newline
\newline
Write your answer in the form
A
A
A
or
A
B
\frac{A}{B}
B
A
, where
A
A
A
and
B
B
B
are constants or variable expressions that have no variables in common. All exponents in your answer should be positive.
\newline
______
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Question
Simplify. Assume all variables are positive.
\newline
x
1
4
x
11
4
\frac{x^{\frac{1}{4}}}{x^{\frac{11}{4}}}
x
4
11
x
4
1
\newline
\newline
Write your answer in the form
A
A
A
or
A
B
\frac{A}{B}
B
A
, where
A
A
A
and
B
B
B
are constants or variable expressions that have no variables in common. All exponents in your answer should be positive.
\newline
______
\newline
Get tutor help
Posted 1 year ago
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