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Let’s check out your problem:
Simplify the expression. Write your answers using
integers
or improper
fractions
.
\newline
−
1
2
(
1
2
h
+
1
2
)
+
4
h
-\frac{1}{2}\left(\frac{1}{2} h+\frac{1}{2}\right)+4 h
−
2
1
(
2
1
h
+
2
1
)
+
4
h
\newline
Answer:
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Math Problems
Algebra 2
Roots of rational numbers
Full solution
Q.
Simplify the expression. Write your answers using integers or improper fractions.
\newline
−
1
2
(
1
2
h
+
1
2
)
+
4
h
-\frac{1}{2}\left(\frac{1}{2} h+\frac{1}{2}\right)+4 h
−
2
1
(
2
1
h
+
2
1
)
+
4
h
\newline
Answer:
Distribute and Simplify:
First, distribute the negative one-half across the terms inside the parentheses.
\newline
−
1
2
(
1
2
h
+
1
2
)
=
−
1
2
⋅
1
2
h
−
1
2
⋅
1
2
-\frac{1}{2}(\frac{1}{2}h+\frac{1}{2}) = -\frac{1}{2}\cdot\frac{1}{2}h - \frac{1}{2}\cdot\frac{1}{2}
−
2
1
(
2
1
h
+
2
1
)
=
−
2
1
⋅
2
1
h
−
2
1
⋅
2
1
Simplify Fractions:
Now, simplify the multiplication of the fractions.
\newline
−
1
2
×
1
2
h
=
−
1
×
1
2
×
2
h
=
−
1
4
h
-\frac{1}{2}\times\frac{1}{2}h = -\frac{1\times1}{2\times2}h = -\frac{1}{4}h
−
2
1
×
2
1
h
=
−
2
×
2
1
×
1
h
=
−
4
1
h
\newline
−
1
2
×
1
2
=
−
1
×
1
2
×
2
=
−
1
4
-\frac{1}{2}\times\frac{1}{2} = -\frac{1\times1}{2\times2} = -\frac{1}{4}
−
2
1
×
2
1
=
−
2
×
2
1
×
1
=
−
4
1
Combine Terms:
Combine the simplified terms with the
4
h
4h
4
h
term that is outside the parentheses.
\newline
−
(
1
4
)
h
−
(
1
4
)
+
4
h
-(\frac{1}{4})h - (\frac{1}{4}) + 4h
−
(
4
1
)
h
−
(
4
1
)
+
4
h
Add Like Terms:
Combine like terms by adding
−
1
4
h
-\frac{1}{4}h
−
4
1
h
and
4
h
4h
4
h
.
\newline
4
h
−
1
4
h
=
16
4
h
−
1
4
h
=
15
4
h
4h - \frac{1}{4}h = \frac{16}{4}h - \frac{1}{4}h = \frac{15}{4}h
4
h
−
4
1
h
=
4
16
h
−
4
1
h
=
4
15
h
Final Simplified Expression:
Now, bring down the constant term
−
(
1
)
/
(
4
)
-(1)/(4)
−
(
1
)
/
(
4
)
. The final simplified expression is
(
15
/
4
)
h
−
(
1
)
/
(
4
)
(15/4)h - (1)/(4)
(
15/4
)
h
−
(
1
)
/
(
4
)
.
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\newline
16
\sqrt{16}
16
\newline
\newline
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\newline
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\newline
9
16
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\newline
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\newline
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\newline
273
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\newline
63
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\newline
−
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Question
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z
z
z
.
\newline
16
=
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16
=
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\newline
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=
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Question
Simplify the radical expression.
14
x
14
\sqrt{14x^{14}}
14
x
14
Write your answer in the form
A
A
A
,
B
\sqrt{B}
B
, or
A
B
A\sqrt{B}
A
B
, where
A
A
A
and
B
B
B
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x
x
x
. Use at most one radical in your answer, and at most one absolute value symbol in your expression for
A
A
A
. ______
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Question
Simplify the radical expression.
\newline
12
x
12
\sqrt{12x^{12}}
12
x
12
\newline
Write your answer in the form
A
A
A
,
B
\sqrt{B}
B
, or
A
B
A\sqrt{B}
A
B
, where
A
A
A
and
B
B
B
are constants or expressions in
x
x
x
. Use at most one radical in your answer, and at most one absolute value symbol in your expression for
A
A
A
.
\newline
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Question
What is the value of
sin
(
5
π
6
)
?
\sin \left(\frac{5 \pi}{6}\right) ?
sin
(
6
5
π
)
?
\newline
Choose
1
1
1
answer:
\newline
(A)
−
3
2
-\frac{\sqrt{3}}{2}
−
2
3
\newline
(B)
−
2
2
-\frac{\sqrt{2}}{2}
−
2
2
\newline
(C)
1
2
\frac{1}{2}
2
1
\newline
(D)
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