Simplify the expression completely. sqrt49+4root(3)(-1000)-root(3)(1)+sqrt(-9) Answer:

Simplify sqrt(49): First, we will simplify each term in the expression separately. The first term is sqrt(49), which is the square root of 49. Calculating the square root of 49 gives us 7, since 7 * 7 = 49.Calculate 4root(3)(-1000): The second term is 4root(3)(-1000), which is 4 times the cube root of -1000. The cube root of -1000 is -10, since (-10) * (-10) * (-10) = -1000. Multiplying this by 4 gives us 4 * (-10) = -40.Find cube root of 1: The third term is root(3)(1), which is the cube root of 1. The cube root of 1 is 1, since 1 * 1 * 1 = 1.Evaluate sqrt(-9): The fourth term is sqrt(-9), which is the square root of a negative number. The square root of a negative number is not a real number; it is an imaginary number. Since we are looking for real-number roots, sqrt(-9) does not have a real value.Combine simplified terms: Now, we combine the simplified terms: 7 (from sqrt(49)) - 40 (from 4root(3)(-1000)) - 1 (from root(3)(1)). The term sqrt(-9) is not included because it is not a real number. Adding and subtracting the real numbers gives us 7 - 40 - 1 = -34.

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Simplify the expression completely.

sqrt49+4root(3)(-1000)-root(3)(1)+sqrt(-9)
Answer:

Simplify the expression completely. $\newline$ $\sqrt{49}+4 \sqrt[3]{-1000}-\sqrt[3]{1}+\sqrt{-9}$ $\newline$ Answer:

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Q. Simplify the expression completely.

\newline

\sqrt{49}+4 \sqrt[3]{-1000}-\sqrt[3]{1}+\sqrt{-9}

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Answer:

Simplify $\sqrt{49}$ : First, we will simplify each term in the expression separately. $\newline$ The first term is $\sqrt{49}$ , which is the square root of $49$ . $\newline$ Calculating the square root of $49$ gives us $7$ , since $7 \times 7 = 49$ .
Calculate $4\sqrt[3]{-1000}$ : The second term is $4\sqrt[3]{-1000}$ , which is $4$ times the cube root of $-1000$ . The cube root of $-1000$ is $-10$ , since $(-10) \times (-10) \times (-10) = -1000$ . Multiplying this by $4$ gives us $4 \times (-10) = -40$ .
Find cube root of $1$ : The third term is $\sqrt[3]{1}$ , which is the cube root of $1$ . $\newline$ The cube root of $1$ is $1$ , since $1 \times 1 \times 1 = 1$ .
Evaluate $\sqrt{-9}$ : The fourth term is $\sqrt{-9}$ , which is the square root of a negative number. The square root of a negative number is not a real number; it is an imaginary number. Since we are looking for real-number roots, $\sqrt{-9}$ does not have a real value.
Combine simplified terms: Now, we combine the simplified terms: $7$ (from $\sqrt{49}$ ) - $40$ (from $4\sqrt[3]{-1000}$ ) - $1$ (from $\sqrt[3]{1}$ ). The term $\sqrt{-9}$ is not included because it is not a real number. Adding and subtracting the real numbers gives us $7 - 40 - 1 = -34$ .