Simplify the expression completely. sqrt(-4)-2root(3)(-125)-3root(3)(-125)+sqrt1 Answer:

Square Root of -4: We need to simplify each term in the expression separately. Let's start with the first term, sqrt(-4). The square root of a negative number involves an imaginary number. The square root of -1 is defined as the imaginary unit i. So, sqrt(-4) = sqrt(4) * sqrt(-1) = 2i.Simplify 2root(3)(-125): Now let's simplify the second term, 2root(3)(-125). The cube root of -125 is -5 because (-5)^3 = -125. So, 2root(3)(-125) = 2 * (-5) = -10.Simplify 3root(3)(-125): Next, we simplify the third term, 3root(3)(-125). Using the same logic as the previous step, 3root(3)(-125) = 3 * (-5) = -15.Square Root of 1: Finally, let's simplify the fourth term, sqrt(1). The square root of 1 is 1 because 1^2 = 1. So, sqrt(1) = 1.Combine Simplified Terms: Now we combine all the simplified terms to get the final simplified expression. 2i - 10 - 15 + 1 = 2i - 24.

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Simplify the expression completely.

sqrt(-4)-2root(3)(-125)-3root(3)(-125)+sqrt1
Answer:

Simplify the expression completely. $\newline$ $\sqrt{-4}-2 \sqrt[3]{-125}-3 \sqrt[3]{-125}+\sqrt{1}$ $\newline$ Answer:

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Algebra 1

Multiplication with rational exponents

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Q. Simplify the expression completely.

\newline

\sqrt{-4}-2 \sqrt[3]{-125}-3 \sqrt[3]{-125}+\sqrt{1}

\newline

Answer:

Square Root of $-4$ : We need to simplify each term in the expression separately. Let's start with the first term, $\sqrt{-4}$ . $\newline$ The square root of a negative number involves an imaginary number. The square root of $-1$ is defined as the imaginary unit $i$ . $\newline$ So, $\sqrt{-4} = \sqrt{4} \times \sqrt{-1} = 2i$ .
Simplify $2\sqrt[3]{-125}$ : Now let's simplify the second term, $2\sqrt[3]{-125}$ . The cube root of $-125$ is $-5$ because $(-5)^3 = -125$ . So, $2\sqrt[3]{-125} = 2 \times (-5) = -10$ .
Simplify $3\sqrt[3]{-125}$ : Next, we simplify the third term, $3\sqrt[3]{-125}$ . Using the same logic as the previous step, $3\sqrt[3]{-125} = 3 \times (-5) = -15$ .
Square Root of $1$ : Finally, let's simplify the fourth term, $\sqrt{1}$ . $\newline$ The square root of $1$ is $1$ because $1^2 = 1$ . $\newline$ So, $\sqrt{1} = 1$ .
Combine Simplified Terms: Now we combine all the simplified terms to get the final simplified expression. $2i - 10 - 15 + 1 = 2i - 24$ .