Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Simplify the expression completely if possible.

(x^(2)-3x-28)/(x^(2)+6x+8)
Answer:

Simplify the expression completely if possible.\newlinex23x28x2+6x+8 \frac{x^{2}-3 x-28}{x^{2}+6 x+8} \newlineAnswer:

Full solution

Q. Simplify the expression completely if possible.\newlinex23x28x2+6x+8 \frac{x^{2}-3 x-28}{x^{2}+6 x+8} \newlineAnswer:
  1. Factor Numerator and Denominator: Factor the numerator and the denominator.\newlineThe given expression is (x23x28)/(x2+6x+8)(x^{2}-3x-28)/(x^{2}+6x+8). We need to factor both the numerator and the denominator to see if there are any common factors that can be canceled out.
  2. Factor Numerator: Factoring the numerator x23x28x^{2}-3x-28. We look for two numbers that multiply to 28-28 and add up to 3-3. These numbers are 7-7 and +4+4. So, x23x28x^{2}-3x-28 can be factored as (x7)(x+4)(x-7)(x+4).
  3. Factor Denominator: Factoring the denominator x2+6x+8x^{2}+6x+8. We look for two numbers that multiply to +8+8 and add up to +6+6. These numbers are +2+2 and +4+4. So, x2+6x+8x^{2}+6x+8 can be factored as (x+2)(x+4)(x+2)(x+4).
  4. Simplify Expression: Simplify the expression by canceling out common factors.\newlineWe have (x7)(x+4)(x-7)(x+4) in the numerator and (x+2)(x+4)(x+2)(x+4) in the denominator. The common factor (x+4)(x+4) can be canceled out from both the numerator and the denominator.\newlineThe simplified expression is x7x+2\frac{x-7}{x+2}.

More problems from Multiplication with rational exponents