Simplify the expression completely if possible. (4x^(2)-4x)/(x^(2)-8x+7) Answer:

Factor Numerator and Denominator: Factor the numerator and the denominator. The numerator 4x^2 - 4x can be factored by taking out the common factor of 4x, resulting in 4x(x - 1). The denominator x^2 - 8x + 7 can be factored into (x - 7)(x - 1) because these are the factors of 7 that add up to -8. So, the expression becomes (4x(x - 1))/((x - 7)(x - 1)).Cancel Common Factors: Cancel out the common factors. The factor (x - 1) is present in both the numerator and the denominator, so we can cancel it out. This leaves us with 4x/(x - 7).Check Further Simplification: Check for any further simplification. There are no common factors left in the numerator and the denominator, and we cannot simplify the expression any further.

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Simplify the expression completely if possible.

(4x^(2)-4x)/(x^(2)-8x+7)
Answer:

Simplify the expression completely if possible. $\newline$ $\frac{4 x^{2}-4 x}{x^{2}-8 x+7}$ $\newline$ Answer:

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Algebra 1

Multiplication with rational exponents

Full solution

Q. Simplify the expression completely if possible.

\newline

\frac{4 x^{2}-4 x}{x^{2}-8 x+7}

\newline

Answer:

Factor Numerator and Denominator: Factor the numerator and the denominator. $\newline$ The numerator $4x^2 - 4x$ can be factored by taking out the common factor of $4x$ , resulting in $4x(x - 1)$ . $\newline$ The denominator $x^2 - 8x + 7$ can be factored into $(x - 7)(x - 1)$ because these are the factors of $7$ that add up to $-8$ . $\newline$ So, the expression becomes $\frac{4x(x - 1)}{(x - 7)(x - 1)}$ .
Cancel Common Factors: Cancel out the common factors. $\newline$ The factor $(x - 1)$ is present in both the numerator and the denominator, so we can cancel it out. $\newline$ This leaves us with $\frac{4x}{(x - 7)}$ .
Check Further Simplification: Check for any further simplification. There are no common factors left in the numerator and the denominator, and we cannot simplify the expression any further.