Simplify the expression completely. 4root(3)(64)-sqrt4+root(3)(-729) Answer:

Find Cube Root of 64: Simplify 4root(3)(64). The cube root of 64 is 4, because 4^3 = 64. So, 4root(3)(64) = 4 * 4 = 16.Find Square Root of 4: Simplify sqrt(4). The square root of 4 is 2, because 2^2 = 4. So, sqrt(4) = 2.Find Cube Root of -729: Simplify root(3)(-729). The cube root of -729 is -9, because (-9)^3 = -729. So, root(3)(-729) = -9.Combine Results: Combine the results from steps 1, 2, and 3. We have 16 from step 1, -2 from step 2 (since we subtract the square root of 4), and -9 from step 3. Combine these values: 16 - 2 - 9.Perform Subtraction: Perform the subtraction. 16 - 2 - 9 = 14 - 9 = 5.

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Simplify the expression completely.

4root(3)(64)-sqrt4+root(3)(-729)
Answer:

Simplify the expression completely. $\newline$ $4 \sqrt[3]{64}-\sqrt{4}+\sqrt[3]{-729}$ $\newline$ Answer:

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Algebra 2

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Q. Simplify the expression completely.

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4 \sqrt[3]{64}-\sqrt{4}+\sqrt[3]{-729}

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Answer:

Find Cube Root of $64$ : Simplify $4\sqrt[3]{64}$ . The cube root of $64$ is $4$ , because $4^3 = 64$ . So, $4\sqrt[3]{64} = 4 \times 4 = 16$ .
Find Square Root of $4$ : Simplify $\sqrt{4}$ . $\newline$ The square root of $4$ is $2$ , because $2^2 = 4$ . $\newline$ So, $\sqrt{4} = 2$ .
Find Cube Root of $-729$ : Simplify $\sqrt[3]{-729}$ . $\newline$ The cube root of $-729$ is $-9$ , because $(-9)^3 = -729$ . $\newline$ So, $\sqrt[3]{-729}$ = $-9$ .
Combine Results: Combine the results from steps $1$ , $2$ , and $3$ . $\newline$ We have $16$ from step $1$ , $-2$ from step $2$ (since we subtract the square root of $4$ ), and $-9$ from step $3$ . $\newline$ Combine these values: $16 - 2 - 9$ .
Perform Subtraction: Perform the subtraction. $16 - 2 - 9 = 14 - 9 = 5$ .