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Let’s check out your problem:
Simplify the expression:
\newline
(
10
d
+
1
)
(
3
)
=
(10d + 1)(3) =
(
10
d
+
1
)
(
3
)
=
_____
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Math Problems
Grade 6
Multiply using the distributive property
Full solution
Q.
Simplify the expression:
\newline
(
10
d
+
1
)
(
3
)
=
(10d + 1)(3) =
(
10
d
+
1
)
(
3
)
=
_____
Distribute and Expand:
Write
(
10
d
+
1
)
(
3
)
(10d + 1)(3)
(
10
d
+
1
)
(
3
)
in expanded form by distributing
3
3
3
to each term inside the parentheses.
\newline
(
10
d
+
1
)
(
3
)
=
3
×
10
d
+
3
×
1
(10d + 1)(3) = 3 \times 10d + 3 \times 1
(
10
d
+
1
)
(
3
)
=
3
×
10
d
+
3
×
1
Perform Multiplication:
Perform the multiplication for each term.
\newline
3
×
10
d
=
30
d
3 \times 10d = 30d
3
×
10
d
=
30
d
and
3
×
1
=
3
3 \times 1 = 3
3
×
1
=
3
, so
(
10
d
+
1
)
(
3
)
=
30
d
+
3
(10d + 1)(3) = 30d + 3
(
10
d
+
1
)
(
3
)
=
30
d
+
3
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A school charges
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\newline
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Question
Which is equal to
cos
6
0
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\newline
(A)
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3
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sin
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(B)
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6
0
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\sin 60^\circ
sin
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Which is equal to
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\newline
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cos
4
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5
∘
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(B)
cos
5
5
∘
\cos 55^\circ
cos
5
5
∘
\newline
(C)
sin
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5
∘
\sin 55^\circ
sin
5
5
∘
\newline
(D)
sin
3
5
∘
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sin
3
5
∘
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\newline
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Which is equal to
sin
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∘
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\newline
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\newline
(A)
cos
6
0
∘
\cos 60^\circ
cos
6
0
∘
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(B)
cos
3
0
∘
\cos 30^\circ
cos
3
0
∘
\newline
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sin
6
0
∘
\sin 60^\circ
sin
6
0
∘
\newline
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sin
3
0
∘
\sin 30^\circ
sin
3
0
∘
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Question
Which is equal to
cos
4
5
∘
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cos
4
5
∘
?
\newline
Choices:
\newline
(A)
sin
4
5
∘
\sin 45^\circ
sin
4
5
∘
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(B)
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5
5
∘
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5
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5
∘
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cos
5
5
∘
\newline
(D)
cos
3
5
∘
\cos 35^\circ
cos
3
5
∘
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