Resourcesdown chevron
Testimonials
Plans
Sign in
Sign up
Resourcesright arrow
Testimonials
Plans
Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Simplify the expression:\newline(1+2b)(2)=(1 + 2b)(2) = _____

View step-by-step helpView step-by-step help
Homeright chevron icon
Math Problemsright chevron icon
Grade 6right chevron icon
Multiply using the distributive propertyright chevron icon

Full solution

Q. Simplify the expression:\newline(1+2b)(2)=(1 + 2b)(2) = _____
  1. Distribute terms: Distribute the 22 to each term inside the parentheses.(1+2b)(2)=2×1+2×2b(1 + 2b)(2) = 2 \times 1 + 2 \times 2b
  2. Perform multiplication: Perform the multiplication. 2×1+2×2b=2+4b2 \times 1 + 2 \times 2b = 2 + 4b
  3. Write simplified expression: Write the simplified expression.\newlineThe expression 2+4b2 + 4b is already simplified, so this is our final answer.

More problems from Multiply using the distributive property

Question
z=6.2+37iRe⁡(z)=Im⁡(z)= \begin{array}{l}z=6.2+37 i \\ \operatorname{Re}(z)= \\ \operatorname{Im}(z)=\end{array}
Get tutor helpright-arrow

Posted 10 months ago

Question
z=4.1i+85Re⁡(z)=Im⁡(z)= \begin{array}{l}z=4.1 i+85 \\ \operatorname{Re}(z)= \\ \operatorname{Im}(z)=\end{array}
Get tutor helpright-arrow

Posted 10 months ago

Question
z=6−3iRe⁡(z)=Im⁡(z)= \begin{array}{l}z=6-3 i \\ \operatorname{Re}(z)= \\ \operatorname{Im}(z)=\end{array}
Get tutor helpright-arrow

Posted 10 months ago

Question
z=14i+12.1Re⁡(z)=Im⁡(z)= \begin{array}{l}z=14 i+12.1 \\ \operatorname{Re}(z)= \\ \operatorname{Im}(z)=\end{array}
Get tutor helpright-arrow

Posted 10 months ago

Question
log⁡1612= \log _{16} \frac{1}{2}=
Get tutor helpright-arrow

Posted 10 months ago

Question
What is the midline equation of\newliney=−4sin⁡(2x−7)+3?y=□ \begin{array}{l} y=-4 \sin (2 x-7)+3 ? \\ y=\square \end{array}
Get tutor helpright-arrow

Posted 10 months ago

Question
What is the midline equation of\newliney=−5cos⁡(2πx+1)−10?y=□ \begin{array}{l} y=-5 \cos (2 \pi x+1)-10 ? \\ y=\square \end{array}
Get tutor helpright-arrow

Posted 10 months ago

Question
What is the midline equation of\newliney=sin⁡(3x+5)?y=□ \begin{array}{l} y=\sin (3 x+5) ? \\ y=\square \end{array}
Get tutor helpright-arrow

Posted 10 months ago

Question
What is the midline equation of\newliney=10cos⁡(6x−1)−4?y=□ \begin{array}{l} y=10 \cos (6 x-1)-4 ? \\ y=\square \end{array}
Get tutor helpright-arrow

Posted 10 months ago

Question
What is the midline equation of\newliney=cos⁡(2π3x)+2?y=□ \begin{array}{l} y=\cos \left(\frac{2 \pi}{3} x\right)+2 ? \\ y=\square \end{array}
Get tutor helpright-arrow

Posted 10 months ago

View all (70)

Related topics

Algebra - Order of OperationsAlgebra - Distributive Property`X` and `Y` AxesGeometry - Scalene TriangleCommon MultipleGeometry - Quadrant