Simplify e^(ln 12-ln 6) and write without any logarithms. Answer:

Apply Logarithm Properties: Apply the properties of logarithms to simplify the expression inside the exponent. The difference of logarithms ln(a) - ln(b) is equivalent to the logarithm of the division of a by b, which is ln(a/b). So, e^(ln 12 - ln 6) becomes e^(ln(12/6)).Simplify Fraction: Simplify the fraction inside the logarithm. 12 divided by 6 equals 2, so e^(ln(12/6)) simplifies to e^(ln 2).Apply Exponential Property: Apply the property of logarithms and exponents that e^(ln x) = x. Since e and ln are inverse functions, e^(ln 2) simplifies to just 2.

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Simplify
e^(ln 12-ln 6) and write without any logarithms.
Answer:

Simplify $e^{\ln 12-\ln 6}$ and write without any logarithms. $\newline$ Answer:

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Q. Simplify

e^{\ln 12-\ln 6}

and write without any logarithms.

\newline

Answer:

Apply Logarithm Properties: Apply the properties of logarithms to simplify the expression inside the exponent. The difference of logarithms $\ln(a) - \ln(b)$ is equivalent to the logarithm of the division of $a$ by $b$ , which is $\ln(\frac{a}{b})$ . So, $e^{(\ln 12 - \ln 6)}$ becomes $e^{(\ln(\frac{12}{6}))}$ .
Simplify Fraction: Simplify the fraction inside the logarithm. $\newline$ $12$ divided by $6$ equals $2$ , so $e^{\ln(\frac{12}{6})}$ simplifies to $e^{\ln 2}$ .
Apply Exponential Property: Apply the property of logarithms and exponents that $e^{\ln x} = x$ . Since $e$ and $\ln$ are inverse functions, $e^{\ln 2}$ simplifies to just $2$ .