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Simplify. Assume all variables are positive.\newlined23d83d83\frac{d^{\frac{2}{3}}}{d^{\frac{8}{3}} \cdot d^{\frac{8}{3}}}\newlineWrite your answer in the form AA or AB\frac{A}{B}, where AA and BB are constants or variable expressions that have no variables in common. All exponents in your answer should be positive.\newline______

Full solution

Q. Simplify. Assume all variables are positive.\newlined23d83d83\frac{d^{\frac{2}{3}}}{d^{\frac{8}{3}} \cdot d^{\frac{8}{3}}}\newlineWrite your answer in the form AA or AB\frac{A}{B}, where AA and BB are constants or variable expressions that have no variables in common. All exponents in your answer should be positive.\newline______
  1. Write Expression: Write down the given expression.\newlineWe have the expression d23/(d83d83)d^{\frac{2}{3}} / (d^{\frac{8}{3}} * d^{\frac{8}{3}}).
  2. Combine Exponents: Combine the exponents in the denominator using the product rule for exponents.\newlineAccording to the product rule, when you multiply two powers with the same base, you add the exponents.\newlineSo, d8/3×d8/3=d8/3+8/3=d16/3.d^{8/3} \times d^{8/3} = d^{8/3 + 8/3} = d^{16/3}.
  3. Rewrite with Combined Exponent: Rewrite the expression with the combined exponent in the denominator.\newlineNow the expression is d23/d163d^{\frac{2}{3}} / d^{\frac{16}{3}}.
  4. Simplify Using Quotient Rule: Simplify the expression using the quotient rule for exponents.\newlineAccording to the quotient rule, when you divide two powers with the same base, you subtract the exponents.\newlineSo, d23/d163=d23163=d143d^{\frac{2}{3}} / d^{\frac{16}{3}} = d^{\frac{2}{3} - \frac{16}{3}} = d^{-\frac{14}{3}}.
  5. Take Reciprocal for Positive Exponent: Since we want the exponent to be positive, we can rewrite the expression with a positive exponent by taking the reciprocal of the base.\newlined(14/3)d^{(-14/3)} is the same as 1/d(14/3)1 / d^{(14/3)}.
  6. Write Final Answer: Write the final answer in the form AA or A/BA/B with positive exponents.\newlineThe final answer is 1d143\frac{1}{d^{\frac{14}{3}}}.

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