Simplify: (-2y^(5))(2y^(4)) Answer:

Identify terms: Identify the terms to be multiplied. We have two terms: (-2y^(5)) and (2y^(4)). We need to multiply these terms together.Multiply coefficients: Multiply the coefficients (numerical parts) of the terms. The coefficients are -2 and 2. Multiplying them together gives us -2 * 2 = -4.Apply product rule: Apply the product rule for exponents. The product rule states that when multiplying two powers that have the same base, you add the exponents. Here, we have y^(5) * y^(4), so we add the exponents 5 and 4 to get 5 + 4 = 9.Combine results: Combine the results from Step 2 and Step 3. We have the coefficient -4 from Step 2 and the exponent result y^(9) from Step 3. Combining these gives us -4y^(9).Check for errors: Check for any possible simplifications or errors. There are no further simplifications possible, and no errors have been made in the calculations.

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Simplify: $\newline$ $\left(-2 y^{5}\right)\left(2 y^{4}\right)$ $\newline$ Answer:

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Algebra 2

Evaluate rational exponents

Full solution

Q. Simplify:

\newline

\left(-2 y^{5}\right)\left(2 y^{4}\right)

\newline

Answer:

Identify terms: Identify the terms to be multiplied. $\newline$ We have two terms: $(-2y^{5})$ and $(2y^{4})$ . We need to multiply these terms together.
Multiply coefficients: Multiply the coefficients (numerical parts) of the terms. $\newline$ The coefficients are $-2$ and $2$ . Multiplying them together gives us $-2 \times 2 = -4$ .
Apply product rule: Apply the product rule for exponents. The product rule states that when multiplying two powers that have the same base, you add the exponents. Here, we have $y^{5} \times y^{4}$ , so we add the exponents $5$ and $4$ to get $5 + 4 = 9$ .
Combine results: Combine the results from Step $2$ and Step $3$ . $\newline$ We have the coefficient $-4$ from Step $2$ and the exponent result $y^{9}$ from Step $3$ . Combining these gives us $-4y^{9}$ .
Check for errors: Check for any possible simplifications or errors. $\newline$ There are no further simplifications possible, and no errors have been made in the calculations.