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Seth is planning a route for a train that travels at a constant rate of 220 kilometers per hour. They want to write an equation that shows how many hours
(t) a trip takes in terms of the trip's distance
(d).
How should Seth write their equation?
Choose 1 answer:
(A)
t=(d)/( 220)
(B)
(d)/(t)=220
(C)
d=220 t

Seth is planning a route for a train that travels at a constant rate of $220$ kilometers per hour. They want to write an equation that shows how many hours $(t)$ a trip takes in terms of the trip's distance $(d)$ . $\newline$ How should Seth write their equation? $\newline$ Choose $1$ answer: $\newline$ (A) $t=\frac{d}{220}$ $\newline$ (B) $\frac{d}{t}=220$ $\newline$ (C) $d=220 t$

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Solve a system of equations using any method: word problems

Full solution

Q. Seth is planning a route for a train that travels at a constant rate of

220

kilometers per hour. They want to write an equation that shows how many hours

(t)

a trip takes in terms of the trip's distance

(d)

.

\newline

How should Seth write their equation?

\newline

Choose

1

answer:

\newline

(A)

t=\frac{d}{220}

\newline

(B)

\frac{d}{t}=220

\newline

(C)

d=220 t

Write Equation: Seth needs to write an equation that relates the distance $d$ to the time $t$ for a train traveling at a constant speed. The formula for distance in terms of speed and time is $d = \text{speed} \times t$ . Since the speed is given as $220$ kilometers per hour, we can substitute speed with $220$ in the formula. $\newline$ Calculation: $d = 220 \times t$
Calculate Time: To find the equation that shows how many hours $t$ a trip takes in terms of the trip's distance $d$ , we need to solve the equation $d = 220 \times t$ for $t$ . $\newline$ Calculation: $t = \frac{d}{220}$
Check Options: Now we need to check the options given to see which one matches the equation $t = \frac{d}{220}$ . Option (A) $t = \frac{d}{220}$ is the correct representation of the equation we derived. Option (B) $\frac{d}{t} = 220$ is the original rate equation, not solved for $t$ . Option (C) $d = 220 \times t$ is the original distance equation, not solved for $t$ .

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