Select the outlier in the data set. 6, 62, 64, 70, 72, 78, 80, 90

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Identify data set: Identify the data set and look for any number that appears to be significantly different from the rest of the numbers. Data set: 6, 62, 64, 70, 72, 78, 80, 90 Looking at the data set, we can see that the number 6 is much smaller than all the other numbers, which are all 62 or higher.Calculate ranges: Calculate the range and the interquartile range (IQR) to determine if 6 is an outlier statistically. First, we need to order the data set from smallest to largest, which is already done. Next, we find the median (the middle value), which is the average of the 4th and 5th values in the ordered list. Median = (70 + 72) / 2 = 71 Since we have an even number of data points, we split the data into two halves to find the first quartile (Q1) and the third quartile (Q3). Lower half: 6, 62, 64, 70 Upper half: 72, 78, 80, 90 Now, we find the median of these two halves. Q1 = Median of lower half = (62 + 64) / 2 = 63 Q3 = Median of upper half = (78 + 80) / 2 = 79 IQR = Q3 - Q1 = 79 - 63 = 16Determine outlier boundaries: Determine the outlier boundaries using the IQR. Lower boundary = Q1 - 1.5 * IQR = 63 - 1.5 * 16 = 63 - 24 = 39 Upper boundary = Q3 + 1.5 * IQR = 79 + 1.5 * 16 = 79 + 24 = 103 Any number below the lower boundary or above the upper boundary is considered an outlier.Compare with boundaries: Compare the data set with the outlier boundaries to identify the outlier. Since 6 is below the lower boundary of 39, it is considered an outlier.

Select the outlier in the data set. $\newline$ $6, 62, 64, 70, 72, 78, 80, 90$

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Select the outlier in the data set.\newline6,62,64,70,72,78,80,906, 62, 64, 70, 72, 78, 80, 906,62,64,70,72,78,80,90

Select the outlier in the data set. $\newline$ $6, 62, 64, 70, 72, 78, 80, 90$