Select the outlier in the data set. 6, 60, 62, 64, 72, 73, 79, 86

Identify Data Set: Step 1: Identify the data set and look for numbers that seem unusually high or low compared to the others. Data set: 6, 60, 62, 64, 72, 73, 79, 86Calculate Range: Step 2: Calculate the range of the data set to see the spread of the numbers. Range = Maximum value - Minimum value Range = 86 - 6 = 80Calculate Mean: Step 3: Calculate the mean (average) of the data set. Mean = (6 + 60 + 62 + 64 + 72 + 73 + 79 + 86) / 8 Mean = 502 / 8 = 62.75Calculate Standard Deviation: Step 4: Calculate the standard deviation to understand how much the values deviate from the mean. Standard deviation involves more complex calculations, so we'll estimate which values are far from the mean. Looking at the data, 6 is much lower than the mean compared to the rest.Compare to Mean: Step 5: Compare each number to the mean and see which is farthest away. 6 is significantly lower than the mean (62.75) and all other numbers.

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Select the outlier in the data set. $\newline$ $6, 60, 62, 64, 72, 73, 79, 86$

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Grade 7

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Q. Select the outlier in the data set.

\newline

6, 60, 62, 64, 72, 73, 79, 86

Identify Data Set: Step $1$ : Identify the data set and look for numbers that seem unusually high or low compared to the others. $\newline$ Data set: $6, 60, 62, 64, 72, 73, 79, 86$
Calculate Range: Step $2$ : Calculate the range of the data set to see the spread of the numbers. $\newline$ Range = Maximum value - Minimum value $\newline$ Range = $86 - 6 = 80$
Calculate Mean: Step $3$ : Calculate the mean (average) of the data set. $\newline$ Mean = $(6 + 60 + 62 + 64 + 72 + 73 + 79 + 86) / 8$ $\newline$ Mean = $502 / 8 = 62.75$
Calculate Standard Deviation: Step $4$ : Calculate the standard deviation to understand how much the values deviate from the mean. Standard deviation involves more complex calculations, so we'll estimate which values are far from the mean. Looking at the data, $6$ is much lower than the mean compared to the rest.
Compare to Mean: Step $5$ : Compare each number to the mean and see which is farthest away. $\newline$ $6$ is significantly lower than the mean $62.75$ and all other numbers.