Select the outlier in the data set. 5, 45, 47, 49, 50, 51, 52, 54, 61

Identify Data Set: Step 1: Identify the data set and look for numbers that seem unusually low or high compared to the others. Data set: 5, 45, 47, 49, 50, 51, 52, 54, 61Calculate Range: Step 2: Calculate the range of the data set to see the spread of the numbers. Range = Maximum value - Minimum value Range = 61 - 5 = 56Calculate Mean: Step 3: Calculate the mean (average) of the data set. Mean = (5 + 45 + 47 + 49 + 50 + 51 + 52 + 54 + 61) / 9 Mean = 414 / 9 = 46Calculate Standard Deviation: Step 4: Calculate the standard deviation to understand how much the values deviate from the mean. Standard deviation involves more complex calculations, so we'll use a simpler approach by observing which number is farthest from the mean.Find Outlier: Step 5: Compare each number to the mean to find the outlier. The number 5 is significantly lower than the mean (46) and all other numbers.

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Select the outlier in the data set. $\newline$ $5, 45, 47, 49, 50, 51, 52, 54, 61$

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Grade 7

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Q. Select the outlier in the data set.

\newline

5, 45, 47, 49, 50, 51, 52, 54, 61

Identify Data Set: Step $1$ : Identify the data set and look for numbers that seem unusually low or high compared to the others. $\newline$ Data set: $5, 45, 47, 49, 50, 51, 52, 54, 61$
Calculate Range: Step $2$ : Calculate the range of the data set to see the spread of the numbers. $\newline$ Range = Maximum value - Minimum value $\newline$ Range = $61 - 5 = 56$
Calculate Mean: Step $3$ : Calculate the mean (average) of the data set. $\newline$ Mean = $(5 + 45 + 47 + 49 + 50 + 51 + 52 + 54 + 61) / 9$ $\newline$ Mean = $414 / 9 = 46$
Calculate Standard Deviation: Step $4$ : Calculate the standard deviation to understand how much the values deviate from the mean. Standard deviation involves more complex calculations, so we'll use a simpler approach by observing which number is farthest from the mean.
Find Outlier: Step $5$ : Compare each number to the mean to find the outlier. $\newline$ The number $5$ is significantly lower than the mean ( $46$ ) and all other numbers.