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Select the outlier in the data set.\newline39,49,59,60,65,72,82,45639, 49, 59, 60, 65, 72, 82, 456\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline39,49,59,60,65,72,82,45639, 49, 59, 60, 65, 72, 82, 456\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier by comparing each value to the rest of the data set.\newlineThe data set is: 39,49,59,60,65,72,82,45639, 49, 59, 60, 65, 72, 82, 456.\newlineClearly, 456456 is much larger than the other values.\newlineOutlier: 456456
  2. Calculate Mean: Calculate the mean of the original data set.\newlineMean = (39+49+59+60+65+72+82+456)/8(39 + 49 + 59 + 60 + 65 + 72 + 82 + 456) / 8\newlineMean = 882/8=110.25882 / 8 = 110.25
  3. Remove Outlier and Recalculate Mean: Remove the outlier and calculate the new mean.\newlineNew data set: 39,49,59,60,65,72,8239, 49, 59, 60, 65, 72, 82\newlineNew mean = (39+49+59+60+65+72+82)/7(39 + 49 + 59 + 60 + 65 + 72 + 82) / 7\newlineNew mean = 426/7=60.86426 / 7 = 60.86
  4. Compare Original and New Mean: Compare the original mean to the new mean.\newlineOriginal mean: 110.25110.25\newlineNew mean: 60.8660.86\newlineSince the new mean is lower, removing the outlier decreases the mean.

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