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Select the outlier in the data set. \newline3,76,84,85,86,89,91,993, 76, 84, 85, 86, 89, 91, 99

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Q. Select the outlier in the data set. \newline3,76,84,85,86,89,91,993, 76, 84, 85, 86, 89, 91, 99
  1. Identify Outlier: Step 11: Identify the data set and look for the number that seems significantly different from the others.\newlineData set: 3,76,84,85,86,89,91,993, 76, 84, 85, 86, 89, 91, 99\newlineLooking at the numbers, 33 stands out as it is much lower than all other numbers which are close to each other in the range of 7676 to 9999.
  2. Calculate Mean: Step 22: Calculate the mean of the other numbers to confirm if 33 is an outlier.\newlineMean calculation: (76+84+85+86+89+91+99)/7=87(76 + 84 + 85 + 86 + 89 + 91 + 99) / 7 = 87\newlineComparing 33 with 8787, it's clear that 33 is far from the mean.
  3. Check Mean Change: Step 33: Check if removing 33 significantly changes the mean, which would support it being an outlier.\newlineNew mean calculation without 33: (76+84+85+86+89+91+99)/7=87(76 + 84 + 85 + 86 + 89 + 91 + 99) / 7 = 87\newlineOriginal mean with 33 included: (3+76+84+85+86+89+91+99)/8=76.625(3 + 76 + 84 + 85 + 86 + 89 + 91 + 99) / 8 = 76.625\newlineThe mean changes significantly, confirming 33 as an outlier.

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