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Select the outlier in the data set.\newline21,26,28,29,32,33,35,60921, 26, 28, 29, 32, 33, 35, 609\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline21,26,28,29,32,33,35,60921, 26, 28, 29, 32, 33, 35, 609\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier by comparing each value to the rest of the data set. The data set is: 21,26,28,29,32,33,35,60921, 26, 28, 29, 32, 33, 35, 609. The value 609609 is much larger than all other values and is therefore the outlier.
  2. Calculate Mean with Outlier: Calculate the mean of the data set including the outlier.\newlineMean = (21+26+28+29+32+33+35+609)/8(21 + 26 + 28 + 29 + 32 + 33 + 35 + 609) / 8\newlineMean = (813)/8(813) / 8\newlineMean = 101.625101.625
  3. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier.\newlineMean without outlier = (21+26+28+29+32+33+35)/7(21 + 26 + 28 + 29 + 32 + 33 + 35) / 7\newlineMean without outlier = (204)/7(204) / 7\newlineMean without outlier 29.14\approx 29.14
  4. Compare Means: Compare the means to determine if the mean would increase or decrease when the outlier is removed.\newlineThe mean without the outlier (29.1429.14) is less than the mean with the outlier (101.625101.625), so the mean would decrease if the outlier were removed.

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