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Select the outlier in the data set.\newline12,22,36,47,61,69,77,82812, 22, 36, 47, 61, 69, 77, 828

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Q. Select the outlier in the data set.\newline12,22,36,47,61,69,77,82812, 22, 36, 47, 61, 69, 77, 828
  1. Calculate mean: Calculate the mean of the data set: (12+22+36+47+61+69+77+828)/8=1153/8=144.125(12 + 22 + 36 + 47 + 61 + 69 + 77 + 828) / 8 = 1153 / 8 = 144.125.
  2. Calculate deviations: Calculate the deviations from the mean for each data point: 12144.125ext,22144.125ext,36144.125ext,47144.125ext,61144.125ext,69144.125ext,77144.125ext,828144.125|12 - 144.125| ext{, } |22 - 144.125| ext{, } |36 - 144.125| ext{, } |47 - 144.125| ext{, } |61 - 144.125| ext{, } |69 - 144.125| ext{, } |77 - 144.125| ext{, } |828 - 144.125|.
  3. Identify largest deviation: Identify the largest deviation: The deviations are 132.125132.125, 122.125122.125, 108.125108.125, 97.12597.125, 83.12583.125, 75.12575.125, 67.12567.125, 683.875683.875. The largest deviation is 683.875683.875, which corresponds to the data point 828828.
  4. Conclude outlier: Conclude that 828828 is the outlier since it has the largest deviation from the mean by a significant margin.

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