Select the outlier in the data set. 1, 35, 41, 42, 43, 44, 45, 47, 50

Identify Outlier: Identify the data set and look for any numbers that appear to be significantly different from the others. Data set: 1, 35, 41, 42, 43, 44, 45, 47, 50 Looking at the data set, we can see that the number 1 is much smaller than all the other numbers, which are all above 35. This suggests that 1 might be the outlier.Calculate Mean: To confirm the outlier, we can calculate the mean (average) of the data set and compare each number to the mean. First, we find the sum of all the numbers in the data set. Sum = 1 + 35 + 41 + 42 + 43 + 44 + 45 + 47 + 50 Sum = 348 Now, we find the mean by dividing the sum by the number of data points. Mean = Sum / Number of data points Mean = 348 / 9 Mean = 38.67 (rounded to two decimal places)Confirm Outlier: Next, we can calculate the standard deviation or look at the distance of each number from the mean to identify the outlier. However, since the number 1 is very far from the mean compared to the other numbers, it is clear that 1 is the outlier without needing to calculate the standard deviation.

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Select the outlier in the data set. $\newline$ $1, 35, 41, 42, 43, 44, 45, 47, 50$

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Q. Select the outlier in the data set.

\newline

1, 35, 41, 42, 43, 44, 45, 47, 50

Identify Outlier: Identify the data set and look for any numbers that appear to be significantly different from the others. $\newline$ Data set: $1, 35, 41, 42, 43, 44, 45, 47, 50$ $\newline$ Looking at the data set, we can see that the number $1$ is much smaller than all the other numbers, which are all above $35$ . This suggests that $1$ might be the outlier.
Calculate Mean: To confirm the outlier, we can calculate the mean (average) of the data set and compare each number to the mean. $\newline$ First, we find the sum of all the numbers in the data set. $\newline$ Sum = $1 + 35 + 41 + 42 + 43 + 44 + 45 + 47 + 50$ $\newline$ Sum = $348$ $\newline$ Now, we find the mean by dividing the sum by the number of data points. $\newline$ Mean = Sum / Number of data points $\newline$ Mean = $348 / 9$ $\newline$ Mean = $38.67$ (rounded to two decimal places)
Confirm Outlier: Next, we can calculate the standard deviation or look at the distance of each number from the mean to identify the outlier. However, since the number $1$ is very far from the mean compared to the other numbers, it is clear that $1$ is the outlier without needing to calculate the standard deviation.