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Select the expression that is equivalent to 
(7x)^(-(1)/(3))

(1)/(sqrt((7x)^(3)))

(1)/(root(3)(7x))

sqrt((7x)^(3))

root(3)(7x)

Select the expression that is equivalent to (7x)13 (7 x)^{-\frac{1}{3}} \newline1(7x)3 \frac{1}{\sqrt{(7 x)^{3}}} \newline17x3 \frac{1}{\sqrt[3]{7 x}} \newline(7x)3 \sqrt{(7 x)^{3}} \newline7x3 \sqrt[3]{7 x}

Full solution

Q. Select the expression that is equivalent to (7x)13 (7 x)^{-\frac{1}{3}} \newline1(7x)3 \frac{1}{\sqrt{(7 x)^{3}}} \newline17x3 \frac{1}{\sqrt[3]{7 x}} \newline(7x)3 \sqrt{(7 x)^{3}} \newline7x3 \sqrt[3]{7 x}
  1. Understand Rule for Negative Exponents: Understand the exponent rule for negative exponents. A negative exponent indicates that the base should be taken as the reciprocal. So, (7x)(13)(7x)^{-(\frac{1}{3})} means we take the reciprocal of (7x)(7x) raised to the positive 13\frac{1}{3} power.
  2. Apply Negative Exponent Rule: Apply the negative exponent rule. Taking the reciprocal of (7x)(7x) to the positive 13\frac{1}{3} power, we get 1(7x)13\frac{1}{(7x)^{\frac{1}{3}}}.
  3. Recognize Meaning of 1/31/3 Exponent: Recognize the meaning of the 1/31/3 exponent.\newlineThe exponent 1/31/3 corresponds to the cube root. Therefore, (7x)1/3(7x)^{1/3} is the cube root of 7x7x.
  4. Combine Reciprocal and Cube Root: Combine the reciprocal and cube root.\newlineThe expression (1)/(7x)(1/3)(1)/(7x)^{(1/3)} is equivalent to taking the cube root of 7x7x and then taking the reciprocal of that result. This gives us the expression (1)/7x3(1)/\sqrt[3]{7x}.

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