Select all the rational numbers. Multi-select Choices: (A)sqrt 2 (B)sqrt 64 (C)root(3) 64 (D)root(3) 27

Define Rational Number: Step 1: Define a rational number. A rational number can be expressed as the quotient of two integers (a fraction) where the denominator is not zero.Evaluate sqrt(2): Step 2: Evaluate Choice (A) sqrt(2). sqrt(2) is known to be an irrational number because it cannot be expressed as a fraction of two integers.Evaluate sqrt(64): Step 3: Evaluate Choice (B) sqrt(64). sqrt(64) equals 8, which is an integer and can be expressed as 8/1, making it a rational number.Evaluate root(3) 64: Step 4: Evaluate Choice (C) root(3) 64. root(3) 64 equals 4, which is an integer and can be expressed as 4/1, making it a rational number.Evaluate root(3) 27: Step 5: Evaluate Choice (D) root(3) 27. root(3) 27 equals 3, which is an integer and can be expressed as 3/1, making it a rational number.

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Select all the rational numbers. $\newline$ Multi-select Choices: $\newline$ (A) $\sqrt{2}$ $\newline$ (B) $\sqrt{64}$ $\newline$ (C) $\sqrt[3]{64}$ $\newline$ (D) $\sqrt[3]{27}$

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Math Problems

Algebra 2

Sum of finite series not start from 1

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Q. Select all the rational numbers.

\newline

Multi-select Choices:

\newline

(A)

\sqrt{2}

\newline

(B)

\sqrt{64}

\newline

(C)

\sqrt[3]{64}

\newline

(D)

\sqrt[3]{27}

Define Rational Number: Step $1$ : Define a rational number. $\newline$ A rational number can be expressed as the quotient of two integers (a fraction) where the denominator is not zero.
Evaluate $\sqrt{2}$ : Step $2$ : Evaluate Choice (A) $\sqrt{2}$ . $\newline$ $\sqrt{2}$ is known to be an irrational number because it cannot be expressed as a fraction of two integers.
Evaluate $\sqrt{64}$ : Step $3$ : Evaluate Choice (B) $\sqrt{64}$ . $\sqrt{64} = 8$ , which is an integer and can be expressed as $\frac{8}{1}$ , making it a rational number.
Evaluate $\sqrt[3]{64}$ : Step $4$ : Evaluate Choice $(C)$ $\sqrt[3]{64}$ . $\sqrt[3]{64}$ equals $4$ , which is an integer and can be expressed as $\frac{4}{1}$ , making it a rational number.
Evaluate $\sqrt[3]{27}$ : Step $5$ : Evaluate Choice (D) $\sqrt[3]{27}$ . $\sqrt[3]{27} = 3$ , which is an integer and can be expressed as $\frac{3}{1}$ , making it a rational number.