Solve the equation using the multiplication property. (2)/(15)=-(y)/(5) The solution set is _____

Identify Equation: Identify the equation to solve. We are given the equation (2)/(15) = -(y)/(5) and we need to find the value of y.Use Multiplication Property: Use the multiplication property of equality to eliminate the fraction. To do this, we can multiply both sides of the equation by the least common multiple (LCM) of the denominators, which is 15. Multiplying both sides by 15 gives us: 15 * (2)/(15) = 15 * -(y)/(5)Simplify Equation: Simplify both sides of the equation. On the left side, the 15 in the numerator and denominator cancel out, leaving us with 2. On the right side, 15 divided by 5 is 3, so we have -3y. So the equation simplifies to: 2 = -3ySolve for y: Solve for y. To isolate y, we divide both sides of the equation by -3. 2 / -3 = -3y / -3 This simplifies to: y = -2/3

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Solve the equation using the multiplication property.
(2)/(15)=-(y)/(5)
The solution set is _____

Solve the equation using the multiplication property. $\newline$ $\frac{2}{15}=-\frac{y}{5}$ $\newline$ The solution set is $\_\_\_\_\_$

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Algebra 1

Multiplication with rational exponents

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Q. Solve the equation using the multiplication property.

\newline

\frac{2}{15}=-\frac{y}{5}

\newline

The solution set is

\_\_\_\_\_

Identify Equation: Identify the equation to solve. $\newline$ We are given the equation $\frac{2}{15} = -\frac{y}{5}$ and we need to find the value of $y$ .
Use Multiplication Property: Use the multiplication property of equality to eliminate the fraction. $\newline$ To do this, we can multiply both sides of the equation by the least common multiple (LCM) of the denominators, which is $15$ . $\newline$ Multiplying both sides by $15$ gives us: $\newline$ $15 \times \frac{2}{15} = 15 \times -\frac{y}{5}$
Simplify Equation: Simplify both sides of the equation. $\newline$ On the left side, the $15$ in the numerator and denominator cancel out, leaving us with $2$ . $\newline$ On the right side, $15$ divided by $5$ is $3$ , so we have $-3y$ . $\newline$ So the equation simplifies to: $\newline$ $2 = -3y$
Solve for y: Solve for y. $\newline$ To isolate y, we divide both sides of the equation by -3＂).$\newline\$\frac{2}{-3} = \frac{-3y}{-3}$$\newline$This simplifies to:$\newline$$y = -\frac{2}{3}$