Scarlett measured a line to be 4.1 inches long. If the actual length of the line is 4.3 inches, then what was the percent error of the measurement, to the nearest tenth of a percent? Answer: %

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Scarlett measured a line to be 4.1 inches long. If the actual length of the line is 4.3 inches, then what was the percent error of the measurement, to the nearest tenth of a percent? Answer:  %

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Understand percent error formula: Understand the percent error formula. Percent error is calculated using the formula:  Percent Error = (|Actual Value - Measured Value| / Actual Value) × 100% Here, the absolute value is used to ensure the error is a positive number.Identify values: Identify the Actual Value and the Measured Value. The Actual Value is given as 4.3 inches, and the Measured Value is given as 4.1 inches.Plug values into formula: Plug the values into the percent error formula. Percent Error = (|4.3 - 4.1| / 4.3) × 100%Calculate absolute difference: Calculate the absolute difference between the Actual Value and the Measured Value. |4.3 - 4.1| = |0.2| = 0.2Divide by Actual Value: Divide the absolute difference by the Actual Value. 0.2 / 4.3 = 0.046511627906976744Multiply by 100: Multiply the result by 100 to get the percent error. 0.046511627906976744 × 100% = 4.651162790697674%Round to nearest tenth: Round the percent error to the nearest tenth of a percent. 4.651162790697674% rounded to the nearest tenth of a percent is 4.7%.

Scarlett measured a line to be $4$ . $1$ inches long. If the actual length of the line is $4$ . $3$ inches, then what was the percent error of the measurement, to the nearest tenth of a percent? $\newline$ Answer:_______ $\%$

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Scarlett measured a line to be $4$ . $1$ inches long. If the actual length of the line is $4$ . $3$ inches, then what was the percent error of the measurement, to the nearest tenth of a percent? $\newline$ Answer:_______ $\%$