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Samuel is the middle of three siblings whose ages are consecutive odd integers. If the sum of their ages is 81 , find Samuel's age.
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Samuel is the middle of three siblings whose ages are consecutive odd integers. If the sum of their ages is 8181 , find Samuel's age.\newlineAnswer:

Full solution

Q. Samuel is the middle of three siblings whose ages are consecutive odd integers. If the sum of their ages is 8181 , find Samuel's age.\newlineAnswer:
  1. Denote Samuel's Age: Let's denote Samuel's age as SS. Since the siblings' ages are consecutive odd integers, the age of the younger sibling will be S2S - 2, and the age of the older sibling will be S+2S + 2. The sum of their ages is given as 8181. So, we can write the equation: (S2)+S+(S+2)=81(S - 2) + S + (S + 2) = 81
  2. Simplify Equation: Now, let's simplify the equation by combining like terms: 3S=813S = 81
  3. Divide by 33: Next, we divide both sides of the equation by 33 to solve for SS:S=813S = \frac{81}{3}S=27S = 27
  4. Check Sum: We have found that Samuel's age is 2727. To ensure there are no math errors, let's check if the sum of the ages is indeed 8181: \newline(272)+27+(27+2)=25+27+29=81(27 - 2) + 27 + (27 + 2) = 25 + 27 + 29 = 81

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