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The cost of a certain number of pens is ₹7272. If the cost of each pen is decreased by ₹11, then 88 more pens can be purchased for the same amount. How many pens can be purchased for the same amount if the cost of each pen is increased by ₹11.5050?

Full solution

Q. The cost of a certain number of pens is ₹7272. If the cost of each pen is decreased by ₹11, then 88 more pens can be purchased for the same amount. How many pens can be purchased for the same amount if the cost of each pen is increased by ₹11.5050?
  1. Define Original Cost: Let xx be the original cost of each pen. Then the number of pens that can be bought for ₹7272 is 72/x72/x.
  2. Calculate New Number of Pens: If the cost of each pen is decreased by ₹11, the new cost per pen is x1x - 1. Then 88 more pens can be bought, so the new number of pens is 72/(x1)72/(x - 1).
  3. Formulate Equation: We have the equation 72x+8=72x1\frac{72}{x} + 8 = \frac{72}{x - 1}.
  4. Clear Denominators: Multiply both sides by x(x1)x(x - 1) to clear the denominators: 72(x1)+8x(x1)=72x72(x - 1) + 8x(x - 1) = 72x.
  5. Simplify Equation: Simplify the equation: 72x72+8x28x=72x72x - 72 + 8x^2 - 8x = 72x.
  6. Combine Like Terms: Combine like terms and move all terms to one side: 8x28x72=08x^2 - 8x - 72 = 0.
  7. Divide by 88: Divide the entire equation by 88 to simplify: x2x9=0x^2 - x - 9 = 0.

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