The cost of a certain number of pens is ₹72. If the cost of each pen is decreased by ₹1, then 8 more pens can be purchased for the same amount. How many pens can be purchased for the same amount if the cost of each pen is increased by ₹1.50?
Q. The cost of a certain number of pens is ₹72. If the cost of each pen is decreased by ₹1, then 8 more pens can be purchased for the same amount. How many pens can be purchased for the same amount if the cost of each pen is increased by ₹1.50?
Define Original Cost: Let x be the original cost of each pen. Then the number of pens that can be bought for ₹72 is 72/x.
Calculate New Number of Pens: If the cost of each pen is decreased by ₹1, the new cost per pen is x−1. Then 8 more pens can be bought, so the new number of pens is 72/(x−1).
Formulate Equation: We have the equation x72+8=x−172.
Clear Denominators: Multiply both sides by x(x−1) to clear the denominators: 72(x−1)+8x(x−1)=72x.
Simplify Equation: Simplify the equation: 72x−72+8x2−8x=72x.
Combine Like Terms: Combine like terms and move all terms to one side: 8x2−8x−72=0.
Divide by 8: Divide the entire equation by 8 to simplify: x2−x−9=0.
More problems from Evaluate variable expressions: word problems